Answer:
25000 fragments
Explanation:
A restriction enzyme can cut a random DNA sequence once per every 4^n where n = number of bases in the recognition site of enzyme.
There are 6 bases in Xbal's recognition site (TCTAGA) so it will cut once per every 4^6 = 4096 bases (4kb).
Total genomic size = 100000kb
So expected number of fragments = Total genomic size/Size of one fragment
= 100000/4
= 25000 fragments
b) A population first divided into two parts, then three parts, and then four parts, until a description identifies a single member.
Hope it will help you ❤️
Inference is d. An observation is something you sense through taste,touch,smell, hear, and see
We all have a common ancestor hence we have some form of a universal genetic code
