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4 years ago

Where do people and animals get energy to move arond

Physics

1 answer:

LuckyWell [14K]4 years ago

6 0

<span>People and animals get energy to move arond in the food they eat.

</span>

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when matter is transformed from a liquid state to the gas state the distance between the particals. and fhe attractive forces be

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Distance increases and force decreases

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4 years ago

A hunter is aiming horizontally at a monkey who is sitting in a tree. The monkey is so terrified when it sees the gun that it fa

Dvinal [7]

Answer:a) The bullet will miss the monkey because the monkey falls down while the bullet speeds straight forward.

Explanation: The bullet keeps as it aim( the monkey) unless it is redirected by an external force that could redirect it. Hence, the bullet speeds straight forward.

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3 years ago

Darna rolls the 7.05-kg ball down the lane and it hits the 1.52-kg pin head on. The ball was moving at 8.24 m/s before the colli

Amiraneli [1.4K]

Answer:

The velocity of the ball after the collision is 5.39 m/s

Explanation:

Hi there!

To solve this problem, we will use the conservation of momentum: the momentum of the system ball-pin remains the same before and after the collision. The momentum of the system is calculated as follows:

momentum before the collision (initial momentum) = mb · vb1 + mp · vp1

momentum after the collision (final momentum) = mb · vb2 + mp · vp2

Where:

mb = mass of the ball = 7.05 kg

vb1 = velocity of the ball before the collision = 8.24 m/s

mp = mass of the pin = 1.52 kg

vp1 = velocity of the pin before the collision = 0 m/s.

vb2 = velocity of the ball after the collsion = unknown.

vp2 = velocity of the pin after the collision = 13.2 m/s

Since momentum is conserved, then:

initial momentum = final momentum

mb · vb1 + mp · vp1 = mb · vb2 + mp · vp2

Solving for vb2:

mb · vb1 + mp · vp1 - mp · vp2 = mb · vb2

(mb · vb1 + mp · vp1 - mp · vp2) / mb = vb2

Since the pin is initially at rest, vp1 = 0:

(mb · vb1 - mp · vp2) / mb = vb2

(7.05 kg · 8.24 m/s - 1.52 kg · 13.2 m/s) / 7.05 kg = vb2

vb2 = 5.39 m/s

The velocity of the ball after the collision is 5.39 m/s

4 0

3 years ago

Squids and octopuses propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracti

Goshia [24]

Answer:

6.78571 m/s

55.13387 Joules

Explanation:

$v_s$ = Velocity of squid = 2.5 m/s

$v_w$ = Velocity of water

$m_w$ = Mass of water = 1.75 kg

Mass of squid

$m_s=6.5-1.75=4.75\ kg$

Momentum of squid

$p_s=m_sv_s\\\Rightarrow p_s=4.75\times 2.5\\\Rightarrow p_s=11.875\ kgm/s$

As the momentum of the system is conserved

$p_s+p_w=0\\\Rightarrow p_s=-p_w\\\Rightarrow 11.875=-p_w\\\Rightarrow 11.875=-m_wv_w\\\Rightarrow v_w=-\frac{11.875}{1.75}\\\Rightarrow v_w=6.78571\ m/s$

The speed of the water is 6.78571 m/s

Kinetic energy the squid creates is given by

Kinetic energy of the squid + Kinetic energy of water

$K=K_s+K_w\\\Rightarrow K=\frac{1}{2}(m_sv_s^2+m_wv_w^2)\\\Rightarrow K=\frac{1}{2}(4.75\times 2.5^2+1.75\times 6.78571^2)\\\Rightarrow K=55.13387\ J$

Kinetic energy the squid creates by this maneuver is 55.13387 Joules

7 0

3 years ago

After a ball is thrown upward and is in the air, what will its acceleration do?

kifflom [539]

Acceleration will always be samei.e.

Acceleration=g= 9.81 m/s^2

8 0

3 years ago