Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
Answer:
=15 1/24
Step-by-step explanation:
18 2/3−3 5/8
=15 1/24
I think the answer is -48°F
Answer:
The result is 60
Step-by-step explanation:
We have to use this expression showing BODMAS rule. According to the rule, we must first solve the brackets. In our expression, the term within the bracket is (12-4) squared = (8) squared = 64.
Then we need to perform the addition followed by subtraction.
The expression becomes:
11 squared - 64 + 3
= 121 - 64 + 3
= 124 - 64
= 60
So, the result of the expression is 60.
