The temperature is 46°F
Step-by-step explanation:
Given the temperatures in F for the past four days as: 45, 38, 46, 35
The mean for the five days is 42 °F
Find the total temperatures with the mean of 42 in 5 days. Perform multiplication
42*5= 210 ° F
Sum of temperature in 4 days is 45+38+46+35=164 °F
The temperatures for the first day will be : 210°F-164°F=46°F
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Mean ; brainly.com/question/256619
Temperature, mean, equation
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Answer:
a
Step-by-step explanation:
1.) 1.47 x 10^4 is the correct answer
You said it yourself... the phrase "900 miles at 30 miles per hour" means that the fraction 900/30=30 is showing how many hours it takes to do 900 miles at a speed of 30 miles an hour. So, it took 30 hours. As with your question, I am not entirely sure of what you are asking, but from the answer choices, the most logical would be the last one, 900 miles/ ? hours. If you implement the number of hours that it takes to drive 900 miles at 30 miles per hour, the fraction would be 900 miles/ ? hours, which would then show the rate that you are driving at, 30 miles per hour.
Any triangle with one angle equal to 90⁰ produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.
<h3>What is the Pythagoras Theorem?</h3>
The Pythagoras theorem states that if a triangle is right-angled (90 degrees), then the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In △ABD and △ACB,
∠A = ∠A (common)
∠ADB = ∠ABC (both are right angles)
Thus, △ABD ∼ △ACB (by AA similarity criterion)
Similarly, we can prove △BCD ∼ △ACB.
Thus △ABD ∼ △ACB,
Therefore, AD/AB = AB/AC.
We can say that AD × AC = AB².
Similarly, △BCD ∼ △ACB.
Therefore,
CD/BC = BC/AC.
We can also say that
CD × AC = BC².
Adding these 2 equations, we get
AB² + BC² = (AD × AC) + (CD × AC)
AB² + BC² =AC(AD +DC)
AB² + BC² = AC²
Hence proved
Thus, any triangle with one angle equal to 90⁰ produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.
Learn more about Pythagoras theorem from:
brainly.com/question/343682
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