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shutvik [7]
4 years ago
8

When looking at attendance data for 2014-2015 school year, a principal graphed number of tardies, x, a student had compared to t

heir grade point average (GPA), y. The principal found the correlation coefficient to be r = -0.94.
There is a ______________ relationship between the number of tardies and the GPA.Immersive Reader

(3 Points)
a.Linear
b.Exponential
c.Quadratic
Mathematics
1 answer:
svetlana [45]4 years ago
4 0

Answer:

a. Linear relationship.

Step-by-step explanation:

Negative correlation describes a relationship of two variables in which one variable increases while the other decreases. It shows the the level at which the variables moves in opposite directions to each other.

In the given example, the two variables are inversely proportional. On plotting the variables against each other, it would have a downward slope. The correlation coefficient, r = -0.94, shows that the number of tardies of a student, x, and grade point average (GPA), y, have a linear relationship. As correlation coefficient is a measure of linear relationship, which could be negative, zero, or positive.

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There are 80 pupils in Jaydon's year group.
ANTONII [103]

Answer:

walk is 24 people

bus is 44 people

Step-by-step explanation:

100% is 80

30% walk

15% bike

55% bus

work out 30%

so 50% is 40

25% is 20 (dived by 2)

5% is 4 (divide 50 by 10)

30% is 24

for bus do 50% is 40

5% is 4

55% is 44 (add)

7 0
3 years ago
Factor completely 49x^2 - 81<br>(7x+9)^2<br>(7x-9)^2<br>(7x+9)(7x-9)<br>7x-9​
AURORKA [14]

Answer:

Step-by-step explanation:

x^{2} -y^{2} =(x+y)(x-y)\\49x^{2}-81=(7{x})^2-{9}^2=(7x+9)(7x-9)

5 0
4 years ago
How many tens are in 90?
inn [45]

Answer:

9

Step-by-step explanation:

You do 90 divided by ten.

8 0
4 years ago
Read 2 more answers
The attractive electric force between point charges q and -2q has a magnitude of 2.2 N when the separation
swat32

Answer:

The Magnitude of charge = q = 15.47 micro coulomb  

Step-by-step explanation:

The attractive force between two points q and - 2 q = F = 2.2 Newton

The separation between two charges = 1.4 meters

Now from Coulomb's law = F = (k \frac{q1 q2}{r^{2}})  where k= 9 \times 10^{9} \frac{N m^{2}}{c^{2}}

So , 2.2 = 9 \times 10^{9} ( (\frac{(q) ( - 2q)}{1.4^{2}})

So , q ² = (\frac{0.479 \times 10^{-9}}{-2})

      For charge magnitude

   I.e q ² = 2.395 \times 10^{-10}

 so, q =  1.547 \times 10^{-5}

      q = 15.47 \times 10^{-6} c

Or,  q = 15.47 micro coulomb

Hence  the Magnitude of charge = q = 15.47 micro coulomb   Answer

4 0
4 years ago
The ratio of the lengths of the sides of a triangle ABC is 3:4:6. M, N, and K are the midpoints of the sides. Perimeter of the △
juin [17]

Given that in a trianlgle the sides AB, BC, CA are in the ratio 3:4:6.

Let AB = 3k, BC = 4k and CA = 6k.

Then perimeter =3k+4k+6k = 13k

M, N, K are mid points of the sides.

By mid point theorem MN = 3k/2, NK = 4k/2 and KM = 6k/2

Hence perimeter of MNK = 13k/2 =5.2 (given)

Solve for k

k=2(5.2)/13 = 0.8

Hence sides are

AB = 3k = 3(0.8) = 2.4 in

BC = 4k= 3.2 in

CA = 4.8 in

7 0
3 years ago
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