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1 answer:
Answer:
The length of AP will be 14 units.
Step-by-step explanation:
As P is the centroid of ΔABC as shown in question figure.
As the side AB of the triangle has the midpoint D, the side AC of the triangle has the midpoint F and the side BC of the triangle has the
midpoint E.
Hence, CD, BF and AE being medians of ΔABC.
The point of intersection of these medians will be the centroid of the triangle. Hence, P is the centroid of ΔABC
According to rule, the centroid point of the triangle ΔABC divides each median into two segments in the ratio 2 : 1.
So,
As the value of AE = 21
So,
AP = 14
So, the length of AP will be 14 units.
Keywords: centroid, triangle
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Answer:
So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).
(There are more values since we can go around the circle from 67 degrees numerous times.)
Step-by-step explanation:
You can use a co-function identity.
The co-function of sine is cosine just like the co-function of cosine is sine.
Notice that cosine is co-(sine).
Anyways co-functions have this identity:
or
You can prove those drawing a right triangle.
I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:
The sum of the angles is 180.
So 90+x+(missing angle)=180.
Let's solve for the missing angle.
Subtract 90 on both sides:
x+(missing angle)=90
Subtract x on both sides:
(missing angle)=90-x.
So the missing angle has measurement (90-x).
So cos(90-x)=a/c
and sin(x)=a/c.
Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).
We can do this also for cos(x) and sin(90-x).
cos(x)=b/c
sin(90-x)=b/c
This means sin(90-x)=cos(x).
So back to the problem:
cos(23)=sin(90-23)
cos(23)=sin(67)
So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).
