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vazorg [7]
3 years ago
6

4. The clutch pedal is found in cars with manual and automatic transmissions.

Computers and Technology
1 answer:
kicyunya [14]3 years ago
8 0
False. The clutch only exists in vehicles with manual transmissions.
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computer is a device for storing and processing data and also to communicate with people

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Is It Safe to Use LinkedIn Automation?
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A lot of people have claimed that they lost their full-established accounts after using LinkedIn automation tools. LinkedIn detected the activity and blocked their accounts.  

But it’s not the tool that causes spam, it’s the approach you adopt while using these tools.  

Many people think that LinkedIn automation tools(LinkedCamp) can generate leads magically over the night. They send thousands of connection requests and messages using automation and as a result, LinkedIn detects their activity.  This is not how it works. You need a proper strategy to leverage the potential of these tools. Even the best LinkedIn automation tools cannot guarantee success if you try to overdo the activities.

6 0
3 years ago
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Write a program that uses an STL List of integers. a. The program will insert two integers, 5 and 6, at the end of the list. Nex
poizon [28]

Answer:

answer:

#include <iostream>

#include<list>

using namespace std;

bool Greater(int x) { return x>3; } int main() { list<int>l; /*Declare the list of integers*/ l.push_back(5); l.push_back(6); /*Insert 5 and 6 at the end of list*/ l.push_front(1); l.push_front(2); /*Insert 1 and 2 in front of the list*/ list<int>::iterator it = l.begin(); advance(it, 2); l.insert(it, 4); /*Insert 4 at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl; l.erase(it); /*Delete the element 4 inserted at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl;

l.remove_if(Greater); for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " ";

/*Display the list*/

cout<<endl; return 0;

}

5 0
3 years ago
Read 2 more answers
Sandy has an entry-level position in a graphic design company. She wants to learn more about the company and the skills she shou
Yakvenalex [24]
The answer should have been B, what was the answer?
8 0
3 years ago
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Consider sending a 2400-byte datagram into a link that has an mtu of 700 bytes. suppose the original datagram is stamped with th
Feliz [49]

Explanation:

Let, DG is the datagram so, DG= 2400.

Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.

Let, M is the MTU so, M=700.

Let, IP is the IP header so, IP= 20.

Let, id is the identification number so, id=422

Required numbers of the fragment = [\frac{DG-IP}{M-IP} ]

Insert values in the formula = [\frac{2400-20}{700-20} ]

Then,        = [\frac{2380}{680} ] = [3.5]

The generated numbers of the fragment is 4

  • If FV = 1 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=0 and F=1.
  • If FV = 2 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=85(85*8=680 bytes) and F=1.
  • If FV = 3 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=170(170*8=1360 bytes) and F=1.
  • If FV = 4 then, bytes in data field of DG= 2380-3(680) = 340 and id=422 and FO=255(255*8=2040 bytes) and F=0.

3 0
4 years ago
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