Consider the equation

1) First row of the table
Set x=0 and solve as follows:

The answer is y=20 and the pair x-y is (0,20)
2) Second row
Set x=1 and solve, as follows:

The answers are y=10 and (1,10)
3) Third row.
Set y=0 and solve as follows:

The answers are x=2 and (2,0)
1.5x + 7 = 20.5
First subtract 7 from both sides
1.5x = 13.5
Then divide both sides by 1.5
x = 9
Let me know in comments if you have questions
Answer:
s=p−(p⋅d) . 0.75p
Step-by-step explanation:
This question is incomplete.
The complete question says;
The two-way table shows the number of hours students studied and whether they studied independently or with a study group.
What is the relative frequency of students that studied independently for more than 2 hours to the total number of students that studied independently?
a) 0.4 c) 0.25
b) 0.33 d) 0.11
Table is attached as image
Answer: C (0.25)
The number of students that studied for more than 2 hours as given in the table are 4.
The total number of people that studied independently include those that studied less than 2 hours and those that studied for more than 2 hours.
Those that studied less than 2 hours independently are 12.
Those that studied more than 2 hours independently are 4.
Hence the total number of people that studied independently is 16.
Therefore the relative frequency of students that studied independently for more than 2 hours to the total number of students that studied independently would be = 4/16 = 1/4 = 0.25.
To solve this problem, we make use of the z statistic. The formula for the z score is:z score = (x – u) / swhere x is the sample value = 0.90, u is the sample mean = 0.917, and s is the standard deviation = 0.005
Therefore:z score = (0.90 – 0.917) / 0.005z score = -3.4
From the standard probability tables, the p-value for a right tailed test of z = -3.4 is:P = 0.9997
Therefore there is a 99.97% chance that it will be above 0.90 mm