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cupoosta [38]
3 years ago
14

Isamu decided to use blocking to deal with an extraneous factor in his experiment. what will blocking do to the subject in his e

xperiment?
a. divide them into groups randomly


b. divide them into groups based on similarities


c. divide them into groups based on an alphabetized list


d. divide them into groups based on whether he likes them
Mathematics
1 answer:
Olegator [25]3 years ago
4 0

Answer:

b. divide them into groups based on similarities

Step-by-step explanation:

Blocking is a method in statistics used to reduce the effect of nuisance variables in an experiment. Nuisance variables are those factors that could result in variations during the experiment. During blocking, subjects with similar features are grouped in the same block, and treatment is then administered to each of these subjects. In order to form blocks, blocking factors are used.

Blocking factors can affect the results of an experiment but they are of no importance to the experimenter. An example of a blocking factor is age.  So, for Isamu who seeks to use blocking to deal with an extraneous factor in his experiment, blocking would enable him to divide his subjects into groups based on similarities.

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(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

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        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

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(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

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        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

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3 years ago
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