Using the equation of the test statistic, it is found that with an increased sample size, the test statistic would decrease and the p-value would increase.
<h3>How to find the p-value of a test?</h3>
It depends on the test statistic z, as follows.
- For a left-tailed test, it is the area under the normal curve to the left of z, which is the <u>p-value of z</u>.
- For a right-tailed test, it is the area under the normal curve to the right of z, which is <u>1 subtracted by the p-value of z</u>.
- For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is <u>2 multiplied by 1 subtracted by the p-value of z</u>.
In all cases, a higher test statistic leads to a lower p-value, and vice-versa.
<h3>What is the equation for the test statistic?</h3>
The equation is given by:
The parameters are:
- is the sample mean.
- is the tested value.
- s is the standard deviation.
From this, it is taken that if the sample size was increased with all other parameters remaining the same, the test statistic would decrease, and the p-value would increase.
You can learn more about p-values at brainly.com/question/26454209
This is a very interesting equation.
Remember: The "solution" to the equation is the number that ' k ' must be
in order to make the equation a true statement.
<u>-3k = -5k</u>
Divide each side of the equation by ' k ' .
Then you have
-3 = -5 .
Is there ANY value for ' k ' that can make that a true statement ?
I don't think so.
This equation has NO solution.
88.50-75=tip=13.5
13.5/75=0.18=18%
18% tip
Answer:
√3
Step-by-step explanation:
To recall trigonometric ratios, there is a special acronym known as sohcahtoa which stands for
- <u>s</u>in(x)=<u>o</u>pposite/ <u>h</u>ypotenuse
- <u>c</u>os(x)=<u>a</u>djacent/<u>h</u>ypotenuse
- <u>t</u>an(x)=<u>o</u>pposite /<u>h</u>ypotenuse
<u>Finding</u><u> the</u><u> </u><u>angle</u><u> </u>
We are given that,
To find the angle , take inverse of sin of both sides,
with the help of unit circle,we acquire:
<u>Finding </u>
simply plug in the value of theta:
using unit circle,we get:
and we're done!