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goldfiish [28.3K]
3 years ago
12

How does acceleration of an object change in relation to its mass

Physics
1 answer:
lina2011 [118]3 years ago
3 0
If the mass is greater the object would accelerate faster
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How you would orient the magnets and what you would do with the magnets to achieve maximum repulsion
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The orientation of the magnets that gives the strongest repulsion because these poles and facing each other that is then leaves highest flux density of the poles for a force of repulsion to be very high

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3 years ago
Consider the following four objects: a hoop, a flat disk, a solid sphere, and a hollow sphere. Each of the objects has mass M an
Mumz [18]

Answer:

The hoop

Explanation:

We need to define the moment of inertia of the different objects, that is,

DISK:

I_{disk} = \frac{1}{2} mR^2

HOOP:

I_{hoop} = mR^2

SOLID SPHERE:

I_{ss} = \frac{2}{5}mR^2

HOLLOW SPHERE

I_{hs} = \frac{2}{3}mR^2

If we have the same acceleration for a Torque applied, then

mR^2>\frac{2}{3}mR^2>\frac{1}{2} mR^2>\frac{2}{5}mR^2

I_{hoop}>I_{hs} >I_{disk}>I_{ss}

The greatest momement of inertia is for the hoop, therefore will require the largest torque to give the same acceleration

4 0
3 years ago
Information about mars' moons.
Alex

Answer:

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2 years ago
Three uniform spheres are located at the corners of an equilateral triangle. each side of the triangle has a length of 1.20 m. t
Andrei [34K]
Refer to the diagram shown below.

Because of symmetry, equal forces, F, exist between the sphere of mass m and each of the other two spheres.
The acceleration of the sphere with mass m will be vertical as shown.

The gravitational constant is G = 6.67408 x 10⁻¹¹ m³/(kg-s²)

Calculate F.
F = [ (6.67408 x 10⁻¹¹ m³/(kg-s²))*(m kg)*(2.8 kg)]/(1.2 m)²
   = 1.2977 x 10⁻¹⁰ m   N

The resultant force acting on mass m is
2Fcos(30°) = 2*(1.2977 x 10⁻¹⁰m N)*cos(30°) = 2.2477 x 10⁻¹⁰m  N

If the initial acceleration of mass m is a m/s², then
(m kg)(a m/s²) = (2.2477 x 10⁻¹⁰m N)
a = 2.2477 x 10⁻¹⁰ m/s²

Answer:
The magnitude of the acceleration on mass m is 2.25 x 10⁻¹⁰ m/s².
The direction of the acceleration is on a line that joins mass m to the midpoint of the line joining the known masses.

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I’ve never went snowmobiling. How is it?
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