Unf there's no diagram. but this looks like a sort of celsius to fahrenheit temp scale conversion sort of problem.
Answer:
1585.67N
Explanation:
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The cyclist is moving by uniformly accelerated motion, with an initial velocity of

and an acceleration of

.
The acceleration is given by

where

is the final velocity and

is the time between the end and the beginning of the motion, and in our case it is 1.75 s. Therefore, from this relationship we can find the final velocity:
The work that is done when twice the load is lifted twice the distance is
four times as much
The net work performed by forces acting on an object equals the change in kinetic energy, according to the work-energy theorem.
when an item slows down, the net work applied to it decreases, its change in kinetic energy is negative, and its ultimate kinetic energy is less than its starting kinetic energy. When an item accelerates, positive net work is done on it. All the forces acting on an item must be taken into consideration when determining the net work. You will obtain an incorrect result if you exclude any forces that affect an item or if you add any forces that do not affect it.
Hence The work that is done when twice the load is lifted twice the distance is four times as much
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