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Alecsey [184]
3 years ago
8

Using the lensmaker's formula (equation (5) of your lab manual), calculate the index of refraction of the acrylic lens. You shou

ld use the f_are you calculated in part (1) above instead of the value for the focal length of the concave lens that you measured. Remember that the focal length of a concave lens is negative so in this case, f = -f_are.
Physics
1 answer:
uysha [10]3 years ago
8 0

Answer:

  n = 1 + R / f

Explanation:

The equation of the constructor is optical is

          1 / f = 1 / p + 1 / q

where f is the focal length, p and q are the distance to the object and image, respectively

The exercise tells us that it is a concave lens with focal length fo, in these lenses the focal length is negative. The relationship to calculate the focal length is

         1 / f = (n -n₀) (1 /R₁ - 1 /R₂)

where is n₀ the refractive index of the medium that surrounds the lens in this case it is air with n₀ = 1, you do not indicate the type of lens, but the most used lens is the concave plane, in this case R₂ = ∞, so which 1 / R₂ = 0, let's substitute

         1 / f = (n-1) / R₁

         n - 1 = R₁ / f

let's calculate

         n = 1- R₁ / f

remember that the radius of curvature is negative, so the equation is

         n = 1 + R / f

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The rate constants for the reactions of atomic chlorine and of hydroxyl radical with ozone are given by 3 × 10-11 e-250/T and 2
Vlada [557]

Answer:

Calculate the ratio of the rates of ozone destruction by these catalysts at 20 km, given that at this altitude the average concentration of OH is about 100 times that of Cl and that the temperature is about -50 °C

Knowing

Rate constants for the reactions of atomic chlorine and of hydroxyl radical with ozone are given by 3x10^{-11} e^{-255/T}  and 2x10^{-12} e^{-940/T}  

T = -50 °C = 223 K

The reaction rate will be given by [Cl] [O3] 3x10^{-11} e^{-255/223} = 9.78^{-12} [Cl] [O3]  

Than, the reaction rate of OH with O3 is

Rate = [OH] [O3] 2x10^{-12} e^{-940/223} = 2.95^{-14} [OH] [O3]

Considering these 2 rates we can realize the ratio of the reaction with Cl to the reaction with OH is 330 * [Cl] / [OH]

Than, the concentration of OH is approximately 100 times of Cl, and the result will be that the reaction with Cl is 3.3 times faster than the  reaction with OH

Calculate the rate constant for ozone destruction by chlorine under conditions in the Antarctic ozone hole, when the temperature is about -80 °C and the concentration of atomic chlorine increases by a factor of one hundred to about 4 × 105 molecules cm-3

Knowing

Rate constants for the reactions of atomic chlorine and of hydroxyl radical with ozone are given by 3x10^{-11} e^{-255/T}  and 2x10^{-12} e^{-940/T}  

T = -80 °C = 193 K

The reaction rate will be given by [Cl] [O3] 3x10^{-11} e^{-255/193} = 8.21^{-12} [Cl] [O3]  

Than, the reaction rate of OH with O3 is

Rate = [OH] [O3] 2x10^{-12} e^{-940/193} = 1.53^{-14} [OH] [O3]

Considering these 2 rates we can realize the ratio of the reaction with Cl to the reaction with OH is 535 * [Cl] / [OH]

Than, considering the concentration of Cl increases by a factor of 100 to about 4 × 10^{5} molecules cm^{-3}, the result will be that the reaction with OH will be 535 + (100 to about 4 × 10^{5} molecules cm^{-3}) times faster than the  reaction with Cl

Explanation:

4 0
3 years ago
What is the law of conservation of energy?
charle [14.2K]
The law of conservation of energy<span>, a fundamental concept of physics, states that the total amount of </span>energy<span> remains constant in an isolated system. It implies that </span>energy<span> can neither be created nor destroyed, but can be change from one form to another.</span>
6 0
3 years ago
What is the mass, in grams, of 2.00 moles of H2O?
tia_tia [17]

Answer:

36g

Explanation:

Given parameters:

Number of moles of H₂O = 2moles

Unknown:

Mass of  H₂O = ?

Solution:

To solve this problem, use the expression below:

   Mass of  H₂O = number of moles x molar mass

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3 0
3 years ago
Use your periodic table to answer the following question.
Pavel [41]
Helium has only 2 electrons in it's valence shell

So, option D is your answer.

Hope this helps!
6 0
3 years ago
A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T on Earth. Calculate the
melamori03 [73]

Answer:

T = T

Explanation:

Time period of a simple pendulum is not affected by the mass of the bob. As we know, T = 2\pi \sqrt{L/g} . There is no factor of mass affecting when we derived the equation. The basic reason behind the time period is not affected is because of mass dependence on angular acceleration. As the mass increases the acceleration increase and the Time Period remains constant.

8 0
3 years ago
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