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ad-work [718]
3 years ago
6

Determine whether a triangle with given side lengths will be a right triangle?

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer:

Step-by-step explanation:

Apply the Pythagorean Theorrem.  Find the sum of the squares of the two shortest sides and determine whether this sum equals the square of the longest side:

#19:  5^2 + 12^2 = ? = 13^2

 25  +  144  = ? = 169    This is true, so you do have a right triange in #19.

#21:  2^2 + 4^2 = ? = 7^2, or 4 + 16 = ? = 49     This is false.  Not a right

                                                                            triangle.

Apply this same approach (Pythagorean Theorem) to the remaining problems.

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Read 2 more answers
Please help
lys-0071 [83]
Part 1
1) The positive integers          ----------->  <span>D.) The natural numbers
</span>2.) An ordering of quantities  -----------> <span>B.) A sequence
</span>3.) 2, 4, 8, 16, . . ., 256            ----------->  <span>A.) An example of a finite sequence
</span>4.) 1, 3, 5, 7, . . .                        ----------->  <span>E.) An example of an infinite sequence
</span>5.) No first term is available   ----------->  C.) The reason the numbers . . . -4, -2, 0, 2, 4, . . . are not a sequence
Part 2
a_n=n^2+2\\ a_1=1+2=3\\ a_2=4+2=6\\ a_3=9+2=11\\ a_4=16+2=18\\ a_5=25+2=27
The answers is A.
Part 3
a_n=-1(\frac{1}{3})^{n-1} \\ a_1=-1(\frac{1}{3})^{1-1}=-1\\ a_2=-1(\frac{1}{3})^{2-1}=-\frac{1}{3}\\ a_3=-1(\frac{1}{3})^{3-1}=--\frac{1}{9}\\ a_4=-1(\frac{1}{3})^{4-1}=--\frac{1}{27}\\ a_5=-1(\frac{1}{3})^{5-1}=--\frac{1}{81}\\
The answers is B.
Part 4
The pattern in this sequence is:
a_n=2a^nb^{n-1}
Let's list first six terms:
a_n=2a^nb^{n-1}\\&#10;a_1=2a^1b^0=2a\\&#10;a_2=2a^2b^1=2a^2b\\&#10;a_3=2a^3b^2\\&#10;a_4=2a^4b^3\\&#10;a_5=2a^5b^4\\&#10;a_6=2a^6b^5\\
This is a infinite sequence. The patern is obvious and we could find any term within the sequence.


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3 years ago
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Answer:

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