Missing question: <span>The decomposition of </span><span> XY is second order in </span><span>and has a rate constant of 6.96×10</span>⁻³ s⁻¹<span> at a certain temperature.
c</span>₀ = 0,050 M.
t = 55 s.
k = 6.96×10⁻³ s⁻¹.
Integrated second
order rate law is: 1/c₁ =
1/c₀<span> + k·t.
</span>1/c₁ = 1/0,050 M + 0,0069 s⁻¹ · 55 s.
1/c₁ = 20,38 1/M.
c₁ = 0,049 M.
<h3>
Answer:</h3>
CaCO₃(s) → CaO(s)+CO₂(g)
<h3>
Explanation:</h3>
We are required to balance the equation given;
We need to ask ourselves some questions;
What is a balanced equation?
- A balanced equation is an equation that has equal number of atom of each element on both sides of the equation.
How do we balance chemical equations?
- Chemical equations are balanced by putting appropriate coefficients on the reactants and products in the equation.
Why is it important to balance chemical equations?
- Chemical equations are balanced to ensure they obey the law of conservation of mass.
- According to the law of conservation of mass, the mass of the reactants should be equal to the mass of the products.
In this case;
The equation given is;
CaCO₃(s) → CaO(s)+CO₂(g)
- The equation is balanced since the number of atoms of each element is equal on both sides of the equation.
- That is, 1 calcium atom, 1 carbon atom and 3 oxygen atom on both sides of the equation.