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3 years ago

Identify all pairs of angles of the given type. alternate interior

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

8 0

Answer:

The answer is 3 and 7; 4 and 8.

Step-by-step explanation:

IDK how to explain this.

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Mat told Sam that for a relation to be a function the input values can repeat but the output values cannot. Sam thought Mrs. Gul

Masteriza [31]

Answer:

Step-by-step explanation:

4 0

3 years ago

Help me plz!!! Wanna know the answer of (d). Thank you so much!!!!

DIA [1.3K]

Answer:

d = -9

Step-by-step explanation:

First lets input our x value for g(x)

This gives us the integral

$g(6) = \int\limits^6_{-4} {f(x)} \, dx$

First, we need to split this integral into the different aspects of the piecewise function. This will give us

$g(6)=\int\limits^0_{-4} {4} \, dx +\int\limits^5_0 {-5} \, dx +\int\limits^6_5 {0} \, dx$

Now, we need to evaluate each of these integrals

$\int\limits^0_{-4} {4} \, dx=4x|\limits^0_{-4}\\\\4(0)-4(-4)=16$

$\int\limits^5_0 {-5} \, dx=-5x|\limits^5_0\\\\-5(5)--5(0)\\\\-25$

$\int\limits^6_5 {0} \, dx=0$

Now all we need to do is add the values of each of these integrals

$16-25=-9$

3 0

4 years ago

Which are solutions of x2=-11+4?

Dovator [93]

For this case we have a quadratic equation of the form:

$ax ^ 2 + bx + c = 0\\x ^ 2 + 11x-4 = 0$

Where:

$a = 1\\b = 11\\c = -4$

We find the roots:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\x = \frac {-11 \pm \sqrt {11 ^ 2-4 (1) (- 4)}} {2 (1)}\\x = \frac {-11 \pm \sqrt {121 + 16}} {2}\\x = \frac {-11 \pm \sqrt {137}} {2}$

The roots are:

$x_ {1} = \frac {-11+ \sqrt {137}} {2}\\x_ {2} = \frac {-11- \sqrt {137}} {2}$

Answer:

$x_ {1} = \frac {-11+ \sqrt {137}} {2}\\x_ {2} = \frac {-11- \sqrt {137}} {2}$

3 0

3 years ago

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Find the midpoint of the segment with endpoints (8, 10) and (5, 2).

Rom4ik [11]

Answer:

midpoint is at (6.5, 6) im pretty sure, im sorry if im wrong

Step-by-step explanation:

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3 years ago

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If<br>a+1/a=4-root15 find a^2 +1/a^2

adelina 88 [10]

62 is the correct answer of this question

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3 years ago

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