Identify all pairs of angles of the given type. alternate interior

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

8 0

Answer:

The answer is 3 and 7; 4 and 8.

Step-by-step explanation:

IDK how to explain this.

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Write an inequality for the graph. Then, in words, describe all the values of that make the inequality true.

kow [346]

-3 > x

The values that make this inequality true are those that are less than -3. The inequality does not include -3.

7 0

2 years ago

If Richard can paint their living room in 4 hours, and Vanessa can paint the same living room in 5 hours, then how long will it

Tju [1.3M]

Answer:

2 hrs 13 mins

Step-by-step explanation:

If Richard can paint the living room in 4 hrs, then in 1 hour he can paint 1/4 of the living .

If Vanessa can paint the living room in 5 hours, then in one hour, she can paint 1/5 of the living room.

In one hour Richard and Vanessa can paint 1/4 + 1/5 = 1/y

y is the number of hours it will take both Richard and Vanessa to paint the living room. 1/y is how much of the house they can paint in one hour.

1/4 + 1/5 = 1/y

(5 + 4)/20. ( find the LCM)

9/20 = 1/y

9y= 20

y = 20/9

y = 2.22hrs

y = 2 hrs 13 mins

4 0

3 years ago

Which phrase best describes the translation from the graph y=(x-5)^2+7 to the graph of y=(x+1)^2-2

Helga [31]

Start from the parent function $f(x)=x^2$

In the first case, you are computing

$f(x-5)+7$

In the second case, you are computing

$f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)$ , you translate the function horizontally, $k$ units left if $k>0$ and $k$ units right if $k$ .

On the other hand, when you transform $f(x) \to f(x)+k$ , you translate the function vertically, $k$ units up if $k>0$ and $k$ units down if $k$ .

So, the first function is the "original" parabola $f(x)=x^2$ , translated $5$ units right and $7$ units up. Likewise, the second function is the "original" parabola $f(x)=x^2$ , translated $1$ units left and $2$ units down.