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Misha Larkins [42]

3 years ago

10

The window and the door are similar rectangles. The door has a width of 4 feet, the wi dow has a width of 30 inches. How many ti

mes greater is the area of the door than the area of the window?

1 answer:

Ipatiy [6.2K]3 years ago

3 0

The area of the door is 16ft (4x4) and the window is 900 (30x30) then do 900/16= 56.25 I hope I'm right!

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A company that manufactures small canoes has a fixed cost of $24,000. It costs $100 to prod canoes produced and sold.) a. Write

sweet-ann [11.9K]

Answer:

a. C(x) = 24,000 + 100x

b. R(x) = 200x

c. Break-even point is 240 canoes

Step-by-step explanation:

a. Cost function is C(x) = FC + pcost * x

C(x) = 24,000 + 100x

Where

FC=Fixed cost = 24,000

pcost=costs to prod canoes = $100

x=produce quantity

b.Revenue function

R(x) = Px * x

R(x) = 200x

Where

Px=Price

x=produce quantity

c. Break-even point is the amount of canoes where revenue are the same as cost. We cover the total cost with the sales.

So, FC + pcost * x=Px * x

24,000 + 100x=200x

Isolating x

24,000 =200x- 100x

100x=24000

x=24,000/100

x=240

3 0

3 years ago

What is -1.2 times 1 1/5 divided by 3/10

djyliett [7]

I think it would be easier to covert the fractions to decimals here

-1.2 * 1 1/5 / 3/10

= -1.2 * 1.2 / 0.3

= -1.44 / 0.3

= - 4.8 answer

6 0

3 years ago

I need help with number 7 and 8 is number 7 right if so skip that and help me figure out how long it would take him to read 9 ch

mamaluj [8]

so 90 x 9 = 980 minutes so that is the answer

3 0

3 years ago

Graph the first six terms of a sequence where a1 = 2 and r = 4.

zavuch27 [327]

We are given with
a1 = 2
r = 4

These are components of a geometric series. The first term is 2 and the common ratio is 4. To get the first six terms, we use the formula:
an = a1 r^(n-1)
a1 = 2 (4)^(1-1) = 2
a2 = 2 (4)^(2-1) = 8
a3 = 2 (4)^(3-1) = 32
a4 = 2 (4)^(4-1) = 128
a5 = 2 (4)^(5-1) = 512
a6 = 2 (4)^(6-1) = 2048

8 0

3 years ago

Read 2 more answers

Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.

anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time² =Speed¹ x Time¹ /Speed²

Time² =Speed¹ x (Time² + 350 seconds ) /Speed²

Time² =0.9 x (Time² + 350 seconds ) /1.9

Time² =0,4737 x (Time² + 350 seconds )

Time² =0,4737 Time² + 165,79 seconds

Time² - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0

3 years ago