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Misha Larkins [42]
3 years ago
10

The window and the door are similar rectangles. The door has a width of 4 feet, the wi dow has a width of 30 inches. How many ti

mes greater is the area of the door than the area of the window?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0
The area of the door is 16ft (4x4) and the window is 900 (30x30) then do 900/16= 56.25 I hope I'm right!
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The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa
horsena [70]

Answer:

7.2 years

Step-by-step explanation:

f(t) =200(1 - 0.956e^{-0.18t})

where f(t) is the length and t is the number of years old

given the Mike measures 148 cm, we need to find out the age

So we plug in 148 for f(t) and solve for t

148 =200(1 - 0.956e^{-0.18t})

divide both sides by 200

\frac{148}{200} = 1 - 0.956e^{-0.18t}

Now subtract 1 from both sides

-0.26= - 0.956e^{-0.18t}

Divide both sides by -0.956

\frac{0.26}{0.956} =e^{-0.18t}

Now take ln on both sides

\frac{0.26}{0.956} =e^{-0.18t}

ln(\frac{0.26}{0.956} )=-0.18tln(e)

ln(\frac{0.26}{0.956} )=-0.18t

divide both sides by -0.18

t=7.2

So 7.2 years

5 0
3 years ago
An archery target consists of a circular bull's-eye with radius x, surrounded by four rings with width y. What is the area of th
amid [387]
<span>given:
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4 0
3 years ago
Answer pwease lol now
Anettt [7]

Answer:

D) y = 27 · (3)^x

Step-by-step explanation:

Replace x with the x values.

27 · (3)^-2 = 27 · 1/9 = 3

27 · (3)^-1 = 27 · 1/3 = 9

27 · (3)^0 = 27 · 1 = 27

27 · (3)^1 = 27 · 3 = 81

17 · (3)^2 = 27 · 9 = 243

D is your answer.

Hope this helps

5 0
2 years ago
What’s the circumference, to this problem ?
jekas [21]

Answer:

9.42 i think

Step-by-step explanation:

3 0
2 years ago
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Which best describes the relationship among the volumes of hemisphere X, cylinder Y, and cone Z?
kogti [31]

Answer: I saw on another post on here with the same question that someone said it was

B. The sum of the volumes of X and Z equals the volume of Y.

6 0
3 years ago
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