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Travka [436]
3 years ago
6

Joe ate 7 pies on wednesday. If that is only 1/4 of the world record for pie eating what is the pie record

Mathematics
2 answers:
SOVA2 [1]3 years ago
6 0
The answer is 24!!!!
Lina20 [59]3 years ago
4 0

Answer:

7 pie is the world record. That is 1/4 under the record and your Answer.

Step-by-step explanation:

Who come up with these dump questions??

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Which one is the correct one giving brainliet
miskamm [114]

Answer:

D

Step-by-step explanation:

Difference means subtraction :)

6 0
2 years ago
Read 2 more answers
Gloria works at the drugstore 5 days a week last week she worked a total of 35 hours she work the same number of hours every day
xz_007 [3.2K]

35 - 11 = 24 \\ 24  \div 4 = 6
she worked 6 hours the other days
4 0
3 years ago
a rectangle has a side length 2x+9 and side width x. If the perimeter is 36 cm, what is the value of x?
alukav5142 [94]
2(2x + 9) + 2(x) = 36

4x + 18 + 2x = 36

Combine like terms.

6x + 18 = 36

Subtract 18 from both sides.

6x = 18

Divide 6 on both sides.

x = 3

Hope this helps!
6 0
3 years ago
The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon
Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about  

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

\bf P(t)= Ce^{kt}

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

\bf P(t)= 10.3e^{kt}

Given that P(10)=12.5

\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936

And the function that models the population growth is

\bf P(t)= 10.3e^{0.01936t}

We need P(20)

\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0
3 years ago
I really need help with all the questions
nlexa [21]
1. 1,728

2. You can't tell because it doesn't say the amount one serving will serve, and how many servings she is serving, and how many people come to her party. Sorry!!

I hope I helped with the first one!
4 0
3 years ago
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