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Fynjy0 [20]
3 years ago
9

The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k

Mathematics
1 answer:
Inga [223]3 years ago
4 0

Answer:

j=4\\k=10

Step-by-step explanation:

8x^3 - 125

\left(2x\right)^3-5^3

Use this formula:

x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)

Where,

x=2x\\y=5

Substitute in the values.

\left(2x\right)^3-5^3=\left(2x-5\right)\left(2^2x^2+5\cdot \:2x+5^2\right)

\left(2x-5\right)\left(4x^2+10x+25\right)

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