The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k

Mathematics

1 answer:

Inga [223]3 years ago

4 0

Answer:

$j=4\\k=10$

Step-by-step explanation:

$8x^3 - 125$

$\left(2x\right)^3-5^3$

Use this formula:

$x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)$

Where,

$x=2x\\y=5$

Substitute in the values.

$\left(2x\right)^3-5^3=\left(2x-5\right)\left(2^2x^2+5\cdot \:2x+5^2\right)$

$\left(2x-5\right)\left(4x^2+10x+25\right)$

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