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balandron [24]
4 years ago
5

Comppete the equation X^2+y^2-10x+6y=15

Mathematics
1 answer:
mart [117]4 years ago
8 0
I believe you meant:  Use completing the square to determine the center and radius of the circle represented by this equation:   <span>X^2+y^2-10x+6y=15

x^2 - 10x + 25 - 25 + y^2 + 6y + 9 - 9 = 15
Then:
     (x-5)^2               +   (y+3)^2            = 24   = 2sqrt(6)

This circle is centered at (5,-3) and has radius 2sqrt(6).</span>
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The expression would be \frac{x^5}{y^8} after the negative exponents have been removed.

A negative exponent basically tells us to "flip" the side of the fraction it's on.  This means that y⁻⁶ on the numerator would go to the denominator, and that x⁻⁴ on the denominator would go to the numerator.  This gives us:

\frac{x\times x^4}{y^2\times y^6}=\frac{x^5}{y^8}
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