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marshall27 [118]
2 years ago
10

The graph of h(x) is shown. Graph of h of x that begins in quadrant two and decreases rapidly following the vertical line which

is 5 units to the left of the y-axis. The curve crosses the x-axis 4 units to the left of the origin and crosses the y-axis one unit below the origin and then continues to decrease to the right in quadrant 4. What are the intercepts and asymptote(s) of h(x)? Explain how to find these using the graph.

Mathematics
2 answers:
fgiga [73]2 years ago
5 0

Answer:

<u>x-intercept</u>

The point at which the curve <u>crosses the x-axis</u>, so when y = 0.

From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)

<u>y-intercept</u>

The point at which the curve <u>crosses the y-axis</u>, so when x = 0.

From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)

<u>Asymptote</u>

A line which the curve gets <u>infinitely close</u> to, but <u>never touches</u>.

From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5

(Please note:  we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).

Firdavs [7]2 years ago
4 0

#1

x intercept is the point where h(x) crosses x axis

  • (-4,0)

y intercept is the point where h(x) crosses y axis

  • (0,-1)

#2

asymptotes are those lines which the function tries to cross but never crosses

Here vertical asymptote is

  • x=-5

The horizontal asymptote is

  • y=-2
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Step-by-step explanation:

The equation will be in standard form when terms are listed in order of decreasing degree, and the right side of the equation is 0.

<h3>Standard form</h3>

We can subtract the right-side expression from both sides to get standard form.

  -3x² -8 -(5x -7) = 5x -7 -(5x -7)

  -3x² -8 -5x +7 = 0 . . . . . . . simplify a bit

  -3x² -5x -1 = 0 . . . . . . . . . collect terms

The standard form equation can be written ...

  -3x² -5x -1 = 0

<h3>Coefficients</h3>

The quadratic coefficient is the coefficient of the term with degree 2. The quadratic coefficient is -3.

The linear coefficient is the coefficient of the term with degree 1. The linear coefficient is -5.

The constant coefficient is the coefficient of the term with no variables. The constant is -1.

__

<em>Additional comment</em>

We can make the leading coefficient positive by multiplying the equation by -1. This gives ...

  3x² +5x +1 = 0

with quadratic, linear, and constant coefficients 3, 5, 1.

This is a legitimate answer to this question. In the case of linear equations, the "standard form" has the constant on the right side of the equal sign, and the leading coefficient is required to be positive. A negative leading coefficient can sometimes lead to errors (when the sign is overlooked), so having a positive leading coefficient is often preferred.

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