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3 years ago

HELP PLEASE:(!!! FIND 0

Mathematics

1 answer:

Debora [2.8K]3 years ago

8 0

Can you come on zooom

Please

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What is the answer to 3a+5-x+7x-2a

Black_prince [1.1K]

The answer to your problem is a+6x+5.

4 0

3 years ago

There are no solutions to the system of inequalities shown below.

mixer [17]

Answer:

False, there are actually infinite solutions as these are parallel lines.

Step-by-step explanation:

3 0

3 years ago

What is the perimeter of this figure?

murzikaleks [220]

Answer:

6+2+3+3+3+5=22 is a correct answer

7 0

3 years ago

Mapiya writes a series of novels. She earned \$75{,}000$75,000dollar sign, 75, comma, 000 for the first book, and her cumulative

qwelly [4]

Answer:

$E(n)=75000 \times 2^n$

Complete question:

write a function that gives mapiyas cumulative earnings E(n), in dollars when she has written n sequel's

Step-by-step explanation:

According to the question, she earned $75000 for the first book.

Also,We are given that her cumulative earnings double with each sequel that she writes.

Assuming she has written n sequel's

Now since we are given that her cumulative earnings double with each sequel

So, her initial earning will be $2^n$ times

So, her earning will be : $75000 \times 2^n$

Now we are given that cumulative earnings is denoted by E(n)

So, the function becomes : $E(n)=75000 \times 2^n$

Hence a function that gives Mapiya's cumulative earnings E(n), in dollars when she has written n sequel's is $E(n)=75000 \times 2^n$

4 0

3 years ago

Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod

goblinko [34]

$(2+3)^{-1}\equiv5^{-1}\pmod7$ is the number L such that

$5L\equiv1\pmod7$

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so L = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

$2a\equiv1\pmod7\implies a\equiv4\pmod7$

since 2*4 = 8, whose residue is 1 mod 7;

$3b\equiv1\pmod7\implies b\equiv5\pmod7$

which we got for free by finding the inverse of 5 earlier. So

$2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7$

and so R = 2.

Then L - R = 1.

6 0

3 years ago