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Andreas93 [3]
3 years ago
6

The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =

2 y = 3 z = 0 z = 2 z = 3 3x-2y+3z=0 (1) -3x - 5y - 5z= -21 (2) x=2 (3)
Mathematics
2 answers:
madreJ [45]3 years ago
8 0
So we are given a system:
3x-2y+3z=0\\
-3x - 5y - 5z= -21
Substitute x = 2 we get the system:
-2y+3z=-6\\
- 5y - 5z= -15
Multiply the first equation by -5 and the second by 2 we get the system:
10y-15z=30\\
- 10y - 10z= -30
Adding the two equations we get :
-25z=0\text{ then}z=0.
We find the value of y by using any of the other equations like this:
-2y=-6\\y=3.
Final solution:
z=0,y=3
Maslowich3 years ago
7 0

Answer:

y = 3

z = 0

Step-by-step explanation:

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A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 0.8 ft/s,
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Answer:

-0.133 radians/s is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall.

Step-by-step explanation:

Let

x= distance between the wall and ladder

Ф = angle between the ladder and ground

The rate of change is: dx/dt = 0.8 ft/s

We need to find dФ/dt when x = 8 ft/s

From the triangle in the figure we see that:

cos Ф = x/10

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d(x)/dt = d/dt (10cosФ)

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(10)^2 = (8)^2+ (Perpendicular)^2

100 = 64 +  (Perpendicular)^2

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(Perpendicular)^2 = 36

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sin Ф = Perpendicular/hypotenuse

sin Ф = 6/10 = 3/5

Putting values in:

dx/dt = -10 sin Ф dФ/dt

0.8 = -10(3/5) dФ/dt

0.8 = -6 dФ/dt

=> dФ/dt = 0.8 / -6

dФ/dt = - 0.133 radians/s

So, -0.133 radians/s is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall.

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