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Andreas93 [3]
2 years ago
6

The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =

2 y = 3 z = 0 z = 2 z = 3 3x-2y+3z=0 (1) -3x - 5y - 5z= -21 (2) x=2 (3)
Mathematics
2 answers:
madreJ [45]2 years ago
8 0
So we are given a system:
3x-2y+3z=0\\
-3x - 5y - 5z= -21
Substitute x = 2 we get the system:
-2y+3z=-6\\
- 5y - 5z= -15
Multiply the first equation by -5 and the second by 2 we get the system:
10y-15z=30\\
- 10y - 10z= -30
Adding the two equations we get :
-25z=0\text{ then}z=0.
We find the value of y by using any of the other equations like this:
-2y=-6\\y=3.
Final solution:
z=0,y=3
Maslowich2 years ago
7 0

Answer:

y = 3

z = 0

Step-by-step explanation:

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6.{6.G.A.4} Find the surface area. Answer without units. *
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3 years ago
570 mL = ? oz,show work
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A projectile is fired straight up from ground level with an initial velocity of 112 ft/s. Its height, h, above the ground after
PtichkaEL [24]

Answer:

Step-by-step explanation:

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Between 3 and 4 seconds is where the projectile reaches a height higher than 192 feet. With a little more work and some calculus you can find the max height to be 196 feet.

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If the Math Olympiad Club consists of 11 students, how many different teams of 3 students can be formed for competitions?
vivado [14]

Answer:

165 different teams of 3 students can be formed for competitions

Step-by-step explanation:

Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:

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  • No matter the order
  • Elements are not repeated

That is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.

To calculate the number of combinations, the following expression is applied:

C=\frac{m!}{n!*(m-n)!}

It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.

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Replacing:

C=\frac{11!}{3!*(11-3)!}

Solving:

C=\frac{11!}{3!*8!}

being:

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So:

C=\frac{39,916,800}{6*40,320}

C= 165

<u><em>165 different teams of 3 students can be formed for competitions</em></u>

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3 years ago
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