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LUCKY_DIMON [66]
3 years ago
7

A rectangle is 29 cm on one side and 6 cm on another side. What is the perimeter?

Mathematics
1 answer:
s2008m [1.1K]3 years ago
5 0

Answer:

70 cm

Step-by-step explanation:

perimeter of rectangle = 2 x (length + width)

2 x (29 + 6) = 70 cm

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The length of a rectangle is fourteen less than two and a half times its width. The perimeter of the
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What is the surface area of a sphere with a radius of 11 units?
postnew [5]

Answer:

Step-by-step explanation:

The surface area of a sphere with radius r is given by

S = 4 pi r^2

for a radius of 11 units,

S =  4 pi 11^2 = 484 pi = 1520.5 sq. units

This does not correspond to any of the answers.

Please check question.

6 0
3 years ago
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3 = x/12 - 4 what is x
alexgriva [62]

Answer:

x=84

Step-by-step explanation:

Add 4 on both sides

3=x/12-4

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Hope this helps! :)

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3 years ago
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Find the first term and the common ratio <br>third term =6 and seventh term= 96​
mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: a_n= a_1r^{n-1}

We are given: third term = 6 i,e

a_3=a_1r(3-1)\\6=a_1r^2----eq(1)

Seventh term = 96

a_7=a_1r(7-1)\\96=a_1r^6----eq(2)

Dividing eq(2) and eq(3)

\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}

So, Common Ratio r = 2

Finding First term using eq(1)

a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}

So, First term a₁ = 3/2 and common ratio r = 2

6 0
3 years ago
In how many ways can we rearrange the digits in the number 12321? With formula and not just listing the numbers.
Archy [21]

Answer:

With a 5-digit number, you have 5 choices for the first digit. There will be 4 digits left so you have 4 choices for the second digit. After you have chosen the first 2 digits there will be 3 remaining so you will have 3 choices for the third digit. Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 2 and 1

7 0
3 years ago
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