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CaHeK987 [17]
3 years ago
14

The simulation kept track of the variables and automatically recorded data on object displacement, velocity, and momentum. If th

e trials were run on a real track with real gliders, using stopwatches and meter sticks for measurement, how might the data compare? Check all that apply. There would be variables that would be hard to control, leading to less reliable data. The data would be just as valid if it were recorded with a stopwatch. Meter sticks may lack precision or may be read incorrectly. Real glider data may vary since real collisions may involve loss of energy. Human error in recording or plotting the data could be a factor. Controlling real glider velocities by hand would be just as accurate as simulation controls.
Physics
2 answers:
Natali5045456 [20]3 years ago
3 0
A I just took the test
laiz [17]3 years ago
3 0

Answer:

in general the data is less accurate than in the simulation

Explanation:

If the measurements were on a real track, some data would be difficult to control, for example the amount of movement. Therefore the results of this parameter would be less reliable.

The bars have a finite width, so that their reading is difficult to match the accuracy of the simulation where the width of the bar is zero.

The other important variable is human error due to several factors, fatigue, parallax, response time, which in the simulation does not exist

The launch speeds of the car by hand have variations due to changes in the person, which in the simulation is always the same

in general the data is less accurate than in the simulation

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What is the focal length of concave mirror that magnifies , by a factor of +3.2 , an object that is placed 30cm from the mirror?
guapka [62]

Answer:

23 cm

Explanation:

The formula for magnification is;

Magnification = image distance / object distance

use values as;

3.2 = v / 30   where v is image distance

v =30*3.2

v=96 cm

The relationship of the focal length with image distance and object distance is expressed as;

\frac{1}{u} +\frac{1}{v} =\frac{1}{f}

where f is the focal length and u is object distance

use values in the equation as;

\frac{1}{30} +\frac{1}{96 }  =\frac{1}{f}

\frac{1}{f} =\frac{7}{160}

f=160/7

f=22.86

f= 23 cm ----------nearest a cm

7 0
3 years ago
A 35 kg child goes down a playground that is inclined at an angle of 27.5 degrees above the horizontal. Find the acceleration if
tigry1 [53]

Answer:

4.16m/s²

Explanation:

According to Newtons second law;

\sum Fx = ma_x\\Fm - Ff = ma_x\\W sin\theta - \mu R cos \theta = ma_x\\mg sin\theta - \mu mg cos\theta = ma_x\\

Fm is the moving force

\mu is  the coefficient of kinetic friction between the child and the slide

m is the mass

g is the acceleration due to gravity

a is the acceleration of the child

Substitute the given values and get the acceleration as shown;

35(9.8)sin27.5 - 0.415(35)(cos27.5) = 35a

158.38-12.88 = 35a

145.49 = 35a

a = 145.49/35

a = 4.16m/s²

Hence the acceleration of the body is  4.16m/s²

4 0
3 years ago
What are the differences between forces and pressure​
slamgirl [31]

Answer:

Force is a push or pull action between objects. Pressure is force acting on a surface area of an object, thus it is force per unit area.

Explanation:

4 0
3 years ago
What are each layer on an atom​
Zarrin [17]
Protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).
5 0
3 years ago
Read 2 more answers
1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and
Arturiano [62]

The time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

<h3>What is center of gravity?</h3>

Any object of mass is attracted towards another by point where whole mass is supposed to be concentrated is called center of gravity.

A 1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and weighing 0.290 N.

The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached.

Taking moments about one end, to find the tension at other end.

Tb X L = WxL/3

here, W is the weight, L is the length of wire and Tb is the tension at point B.

So, Tb = W/3

and
Tb - Ta = W

here, Ta is the tension in end A.

Substitute the values, we get

Tb = 583.33N and Ta = 1166.66N

Velocity of end A, Va = (1166.66 x1.25 x 9.81/0.290 )^(1/2)

Va = 222 m/s

Velocity of end B, Vb = (583.33 x1.25 x 9.81/0.290 )^(1/2)

Va = 157 m/s

Time delay t is related with the velocities as

t = L/Vb - L/Va

Substitute the values, we get

t= 0.00233 s

t = 2.33 ms

Thus, time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

Learn more about center of gravity.

brainly.com/question/20662235

#SPJ1

8 0
2 years ago
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