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Igoryamba
2 years ago
9

Compare and contrast the electric forces with the gravitational force.

Physics
1 answer:
Rudik [331]2 years ago
8 0

Answer:

They both act between two bodies without any means of contact. However gravitational force acts on mass while the electric force acts on charge. Gravitational force are only attractive while electric field can be attractive/repulsive. Electric field is much stronger than gravitational field.

Explanation:

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What do you think would happen to the boiling point of water if you were to cook pasta near the Dead Sea in Israel, which is 1,2
mina [271]

Answer:

I think it will be the same.

5 0
3 years ago
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A man walke towards the bus stop 100 meters away at a constant velocity. He reaches the bus stop in 200 seconds. Once at the bus
serg [7]
First:

d = 100 m
t = 200 sec

v = 100/200 = 0.5 m/s

Displacement is zero since he returned to his start point.

t2 = d/v2 = 100/2 = 50 sec

total time = 50 + 200 + 500 = 750 sec
3 0
4 years ago
A 2.00 kg, frictionless block s attached to an ideal spring with force constant 550 N/m. At t = 0 the spring is neither stretche
gladu [14]

Answer:

a)    A = 0.603 m , b) a = 165.8 m / s² , c)  F = 331.7 N

Explanation:

For this exercise we use the law of conservation of energy

Starting point before touching the spring

    Em₀ = K = ½ m v²

End Point with fully compressed spring

    Em_{f} = K_{e} = ½ k x²

    Emo = Em_{f}

    ½ m v² = ½ k x²

    x = √(m / k)    v

    x = √ (2.00 / 550)   10.0

    x = 0.603 m

This is the maximum compression corresponding to the range of motion

     A = 0.603 m

b) Let's write Newton's second law at the point of maximum compression

    F = m a

    k x = ma

    a = k / m x

    a = 550 / 2.00 0.603

    a = 165.8 m / s²

With direction to the right (positive)

c) The value of the elastic force, let's calculate

    F = k x

    F = 550 0.603

   F = 331.65 N

5 0
3 years ago
PLEASE HELPPP!!! I'LL GIVE BRAINLEST FOR CORRECT ANSWERS​
babymother [125]

Answer:

Explanation:

Weight will be highest at the pole where there is no tangential velocity requiring centripetal acceleration. Also, due to the slight bulge of the earth at the equator, the distance from the surface to the center of mass of earth is slightly shorter there meaning gravity is slightly stronger. Fg = GmM/R²

Weight will be lowest at the equator where the object is moving about the earth axis at an angular velocity of 2π/(24(3600)) rad/s ( about 7.27e-5 rad/s)

This means that some of the (already weaker, see above) gravity there is required to supply the needed centripetal acceleration to keep the object on the ground.

4 0
3 years ago
Two identical small charged spheres are a certain distance apart, and each initially experiences an electrostatic force of magni
Rom4ik [11]

Answer:

New force, F'=\dfrac{1}{4}F

Explanation:

The electrostatic force between two spheres is given by :

F=\dfrac{kq_1q_2}{r^2}

According to given condition, each of the spheres has lost half its initial charge, new force is given by :

F'=\dfrac{kq_1/2q_2/2}{r^2}

F'=\dfrac{1}{4}\times \dfrac{kq_1q_2}{r^2}

F'=\dfrac{1}{4}F

So, the new force becomes (1/4)th of the initial force. Hence, the correct option is (d).                  

4 0
4 years ago
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