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Paul [167]
3 years ago
14

Gravity holds planets in orbit because planets are attracted to each other’s gravitational force true or false

Physics
2 answers:
Nezavi [6.7K]3 years ago
6 0
It's true that gravity holds planets in orbit. However, this is due to the gravitational influence of the sun, not the gravitational influence of other planets.
Tema [17]3 years ago
6 0

Answer: Hello mate!

The orbit of the planets is around the sun, which means that the principal contribution in the forces is due to the sun's gravity.

But, it is true that planets experience a gravitational force due other planets, and this also contributes to the actual orbits (suppose that you "remove" a planet, then the orbit of the other planets may change)

So this is false; the actual statement would be true if it was:

"Gravity holds planets in orbit because planets are attracted to each other’s and the sun gravitational force."

And there are other contributors, like satellites and such, but those are really minor compared with the previous contributions.

You might be interested in
Two runners start at a distance of 10 miles from each other. They run towards each other at a constant velocity of 5 mph. A fly
Elena L [17]

Answer:

The fly will travel 20 miles before the runners collide with each other.

Explanation:

Since the runners are both traveling at the same speed, they will meet and collide in the exact middle of each other which is 5 miles away from their starting point. Since they are traveling at 5 mph, it will take exactly one hour before they collide. The fly is going 20 mph so it will travel 20 miles before the runners collide in one hour.

5 0
3 years ago
What was Neptune's distance from the Sun in 1989?
Studentka2010 [4]

Answer:

4.5 Billion km :)

Explanation:

thats how it is

7 0
4 years ago
Read 2 more answers
I really need help on this question!
Mrac [35]

Answer:

the 2nd one

Explanation:

8 0
3 years ago
1. Consider a circular track with a radius of 200 meters. A runner starts on the east side and runs around the track to a point
ladessa [460]

Answer:

The magnitude of her displacement when at a point diametrically opposite her starting point is 400 meters

After she has returned to her starting point, the magnitude of her displacement is zero

Explanation:

Displacement is a vector quantity defined as the length of the shortest path between the final and the initial points. In other words, displacement can be defined as the distance traveled in a straight line.

From the question,

The circular track has a radius of 200 meters.

The runner starts on the east side to a point diametrically opposite her starting point. The diametrically opposite point is the point at the opposite end of the diameter of the circle.

Hence, her displacement ( that is, the length of the shortest path between her final and her initial points) is the length of the diameter of the circle.

Diameter d, of a circle is given as twice the radius r, of the circle.

That is, d = 2r

Radius r, of the circular track is 200 meters

∴ d = 2r = 2 (200 meters)

d = 400 meters

Hence, her displacement when at a point diametrically opposite her starting point is 400 meters

Now, after she has returned to her starting point, the magnitude of her displacement is zero.

This is because, the length between her final point ( which is the same as her initial point) and her initial point in zero.

7 0
3 years ago
If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu
zubka84 [21]

Answer:

minimum speed is 15.35 m/s

frictional coefficient  is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and   minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² =  236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 =  0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245  = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient  is 0.26

4 0
3 years ago
Read 2 more answers
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