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strojnjashka [21]
3 years ago
7

Ruiz needs to buy a countertop for a kitchen. He calculated the area to be 16 square feet. The actual area is 15.4 square feet.

What is Ruiz's percentage error?
(How do you solve this?)
Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:3.9%

Step-by-step explanation:

16-15.4=0.6

0.6/15.4=3.89610

3.89610*100%=3.9%

Marina86 [1]3 years ago
4 0
First, subtract the two values:

16 - 15.4 = 0.6

Now divide this to the actual area:

0.6 / 15.4 = 0.038961039

Multiply by 100:

0.038961039 * 100 = 3.8961039

So the percent error is approximately 3.9%
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Convert 4/12 into a decimal round to the nearest tenths place
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0.3

Step-by-step explanation:

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In ΔNOP, n = 170 inches, o = 150 inches and p=290 inches. Find the measure of ∠P to the nearest 10th of a degree.
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3 years ago
Which of the following expressions shows how to rewrite 5 − 6 using the additive inverse and displays the expression correctly o
Andru [333]

The correct display of the expression on a number line is number line (c)

<h3>How to determine the expression that shows how to rewrite 5 − 6 using the additive inverse?</h3>

The complete question is added as an attachment

The expression is given as:

5 - 6

Put 6 in a bracket.

So, we have:

5 - 6 = 5 - (6)

Express 6 as --6

So, we have:

5 - 6 = 5 - -(-6)

Rewrite as:

5 - 6 = 5 + (-6)

The above means that the arrow on the number line must start from 5 and moves in the negative direction in 6 units

The correct display of the expression on a number line is number line (c)

Read more about number lines at:

brainly.com/question/24644930

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7 0
2 years ago
Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function
dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

f(x)=x^3+2x^2-x-2

The y-intercept occurs when x=0, so:

f(0)=(0)^3+2(0)^2-(0)-2=-2

Therefore, the y-intercept is the given by the point:

\boxed{(0,-2)}

From the figure we have three x-intercepts:

\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}

So, the x-intercepts occur when y=0. Thus, proving this:

f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0

7 0
3 years ago
Read 2 more answers
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