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3 years ago

12

andy is scuba diving he starts at sea level and then descends 10 feet in 2 1/2 minutes. how would you represent andy’s descent a

s a unit rate? express your answer as an integer

1 answer:

UNO [17]3 years ago

6 0

Answer:

4 feet/minute

explanation:

The rate of descent = (10 feet)/(2.5 mn) = 4 ft/min

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Find the surface area and please explain

dlinn [17]

Answer:

I NEED MORE DETAILS

Step-by-step explanation:

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8 0

3 years ago

The formula a = 118e0.024t models the population of a particular city, in thousands, t years after 1998. when will the populatio

andriy [413]

Given that the population has been modeled by the formula:
a=118e^(0.024t), the time taken for the population to hit 140k will be given by:
140000=118e^(0.024t)
solving for t we shall have:
140000/118=e^(0.024t)
thus;
0.024t=ln(140000/118)
t=1/0.024*ln(140000/118)
t=295
thus the time the population will be 140000 will be:
1998+295
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6 0

3 years ago

Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3

Whitepunk [10]

If $f(x)=4x-3$ :

$\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4$

If $f(x)=4x^{-3}$ :

$\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}$

$\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}$

$\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}$

7 0

4 years ago

The width of a rectangle is 2 cm less than 8 times the length. The perimeter is 68 cm. What are the width and length of the rect

eduard

Answer:

length=4

width=30

Step-by-step explanation:

length=x

width=8x-2

(8x-2)*2+2x=68

16x-4+2x=68

18x=72

x=4 (Length)

4*8=32, 32-2=30(width)

8 0

3 years ago

Read 2 more answers

UVOISINOULLIV HU

Gala2k [10]

<h3>Total snow fall for three days is 8.75 inches</h3>

<em><u>Solution:</u></em>

Given that,

Snow fell over the past three days

$First\ day = 3\frac{2}{4}\ inches = \frac{14}{4}\ inches\\\\Second\ day = 3\frac{2}{4}\ inches = \frac{14}{4}\ inches\\\\Third\ day = 1\frac{3}{4}\ inches = \frac{7}{4}\ inches$

<em><u>What was the total snowfall for the three days?</u></em>

Total snowfall = first day + second day + third day

$Total\ snowfall = \frac{14}{4} + \frac{14}{4} + \frac{7}{4}\\\\Total\ snowfall = \frac{14 + 14 + 7}{4}\\\\Total\ snowfall = \frac{35}{4} \text{ or } 8.75\ inches$

Thus total snow fall for three days is 8.75 inches

5 0

3 years ago