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Deffense [45]
3 years ago
12

How do I solve this equation q(a+y)=67y+93

Mathematics
1 answer:
adell [148]3 years ago
8 0
A= 67y+93/q-y; q=/0
..........
You might be interested in
Describe and correct the error in finding the area of a sector with a radius of 6 centimeters and a central angle of 40
Jet001 [13]

Answer:

12.56

Step-by-step explanation:

Remark

Since we don't have anything other than the question, all I can do is answer the question. You are left with the task of figuring out the error.

Formula

Area = (central angle divided by 360 ) * pi r^2

Solution

Area = (40 /360) * 3.14 * 6^2

Area = 1/9 * 3.14 * 36

Area = 4 * 3.14

Area = 12.56

8 0
3 years ago
How many days will it take for a culture of bacteria to increase from 200 to 50000 if the growth rate per day is 93.2%
densk [106]

Answer:

89 days

Step-by-step explanation:

5 0
3 years ago
If a bloodstain has a length of 3.0cm and a width of 1.5cm what is the angle of impact?
zalisa [80]

The angle of impact is 30°

<h3>What is the angle of impact?</h3>

In a bloodstain, the angle of impact can be used to determine the appearance of the resulting bloodstain if the bloodstain has a tail or pattern.

  • Bloodstain pattern analysis is the study of bloodstains at a scene of the crime in an attempt to reconstruct the events that resulted in the bloodshed.

Mathematically;

\mathbf{Angle  \ of \  impact = sin^{-1} (\dfrac{width \ stain}{length \ stain} )}

\mathbf{Angle  \ of \  impact = sin^{-1} (\dfrac{1.5}{3.0} )}

\mathbf{Angle  \ of \  impact = 30 ^0}

Learn more about the angle of impact here:
brainly.com/question/19423063

6 0
2 years ago
1. question in attachment
skelet666 [1.2K]
Was there a chart with this?
4 0
3 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
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