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Deffense [45]
3 years ago
12

How do I solve this equation q(a+y)=67y+93

Mathematics
1 answer:
adell [148]3 years ago
8 0
A= 67y+93/q-y; q=/0
..........
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Write the equation of the line that passes through the points (-6,5) and (3,−5). Put your answer in fully reduced point-slope fo
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Answer:

\displaystyle y-5=-\frac{10}{9}(x+6)

Or:

\displaystyle y+5=-\frac{10}{9}(x-3)

Step-by-step explanation:

We want to write the equation of a line that passes through the points (-6, 5) and (3, -5) in point-slope form.

Point-slope form is given by:

y-y_1=m(x-x_1)

Thus, first, we need to find the slope. We can use the slope formula:

\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{(-5)-(5)}{(3)-(-6)}=\frac{-10}{9}=-\frac{10}{9}

Next, we can use either of the two given points. I'll use (-6, 5). So, let (-6, 5) be (<em>x₁, y₁</em>). Substitute:

\displaystyle y-(5)=-\frac{10}{9}(x-(-6))

Or, fully simplified:

\displaystyle y-5=\frac{-10}{9}(x+6)

Using the other point, we will acquire:

\displaystyle y-(-5)=-\frac{10}{9}(x-(3))

Or, simplified:

\displaystyle y+5=-\frac{10}{9}(x-3)

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