Answer:
Step-by-step explanation:
If you have an odd number of consecutive numbers, the middle number should be x. So 7 of them would be written as
(x - 3)+(x - 2) + (x - 1) + x + (x + 1) + (x + 2) + (x+3)
That way all you are left with is 7x because the integers cancel.
That is not your question
You question is
Sum = m+(m + 1) + (m + 2) + (m + 3) + (m + 4) + (m + 5) + (m + 6)
1 would have the greater value since it is a whole number unlike .38 which is less than a whole
Hope that answered your question
<span>The 3rd astronaut would catch the 2nd astronaut and throw the 2nd astronaut towards the 1st and the game would end there.
The key thing to remember is conservation of momentum. Since all of the astronauts have the same mass and strength, I will be introducing a unit called "A" which represents the maximum momentum that one astronaut can produce while throwing another. So here's the game of catch, throw by throw.
Before the game begins, I will assume all three astronauts are stationary and have 0 momentum. So
Astronaut 1 = 0 A (Stationary, next to astronaut 2)
Astronaut 2 = 0 A (Stationary, next to astronaut 1)
Astronaut 3 = 0 A (Stationary)
1st astronaut grabs the 2nd astronaut and throws him towards the 3rd.
Since every action has an equal and opposite reaction, what will happen is the 1st astronaut will be sent moving backwards with a momentum of -1/2A and the 2nd astronaut will be heading towards the 3rd with a momentum of +1/A. So we're left with
Astronaut 1 = -1/2 A (Moving to the left)
Astronaut 2 = +1/2 A (Moving to the right)
Astronaut 3 = 0 A (Stationary)
Now the 3rd astronaut catches the 2nd who was thrown at him. Both of them continue moving in the same direction as the 2nd astronaut was just prior to being caught, but at a reduced velocity, giving
Astronaut 1 = -1/2 A (Moving to the left)
Astronaut 2 = +1/4 A (Moving to the right, slowly)
Astronaut 3 = +1/4 A (Moving to the right, slowly)
Finally, Astronaut 3 throws astronaut 2 back towards Astronaut 1, giving
Astronaut 1 = -1/2 A (Moving to the left)
Astronaut 2 = +1/4 A -1/2A = -1/4A (Moving to the left, slowly)
Astronaut 3 = +1/4 A +1/2A = +3/4A (Moving to the right, rapidly)
So what you're left with is Astronaut 1 moving to the left faster than Astronaut 2, so those two astronauts will never catch each other. Meanwhile, Astronaut 3 is moving to the right and getting further and further away from the other 2 astronauts. So none of the astronauts will ever be able to catch or throw anyone ever again.</span>
x = All real numbers or 0.
First you should distribute both sides of the equation. This gives you 42x+42=42x+42.
Then, subtract 42 from both sides. This gives you 42x=42x.
Now, divide 42 on both sides. This gives you x=0 or all real numbers.
Quotient is another name for the answer to a division problem
the hundreds place is the 3rd number before the decimal, 9999999.0
^this one
so you need to find a division problem that equals something between 100 and 999
1000 divided by 10 is a good one, the answer to that problem is 100, and 100 has its first digit in the hundreds place.
