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MrMuchimi
2 years ago
13

In a raffle, 200 tickets are sold.

Mathematics
2 answers:
vlabodo [156]2 years ago
6 0

Answer:

0%

Step-by-step explanation:

KiRa [710]2 years ago
3 0

Answer:

there is a zero percent chance that the winning ticket will be green if all of the tickets are either red or blue

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Show another way to write 100 more than 623 ​
____ [38]
There are many ways, but here is one:

x = 100

Since ‘x’ is 100 and we want 100 more, we just need to add ‘x’ to 623

Answer: x + 623 (Make sure you define your ‘x’ value)
4 0
3 years ago
there are 3 black marbles in and 4 red marbles in a bag. what is the probability that you will pick two black marbles put of the
professor190 [17]

|\Omega|=7\cdot6=42\\ |A|=3\cdot2=6\\\\ P(A)=\dfrac{6}{42}=\dfrac{1}{7}\approx14\%

5 0
3 years ago
Given two angles in each triangle, how can you determine if two triangles are similar?​
goldenfox [79]

Answer:

If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion.

Step-by-step explanation:

can you please mark me as brainliest

7 0
2 years ago
Read 2 more answers
A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.
arlik [135]
Given: 11-pound mixture of peanuts, almonds, and raisins
Cost:
peanuts - 1.5 per pound
almonds - 3 per pound
raisins - 1.5 per pound

mixture:
twice as many peanuts as almond; total cost of mixture is 21.

a + p + r = 11 lbs
a + 2a + r = 11 lbs
3a + r = 11
r = 11 - 3a

1.5(2a) + 3a + 1.5r = 21
3a + 3a + 1.5r = 21
6a + 1.5r = 21
6a + 1.5(11-3a) = 21
6a + 16.5 - 4.5a = 21
6a - 4.5a = 21 - 16.5
1.5a = 4.5
1.5a/1.5 = 4.5/1.5
a = 3

almonds = 3 lbs
peanuts = 2a = 2(3) = 6lbs
raisins = 11 - 3a = 11 - 3(3) = 11 - 9 = 2 lbs

<span>My answer is: C. 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins </span>
8 0
3 years ago
Read 2 more answers
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
Read 2 more answers
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