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3 years ago

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There is a store where people enter at a rate of 3 for each day. what is the probability that this store will have at least two

customers for more than 5 days per week?

1 answer:

OverLord2011 [107]3 years ago

8 0

If 3 people are going to the store each day
the probablity is 100%

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A. In two or more complete sentences, explain how to find the exact value of sec 13pi/6 including quadrant location

Sergio039 [100]

Answer:

A. The exact value of sec(13π/6) = 2√3/3

B. The exact value of cot(7π/4) = -1

Step-by-step explanation:

* Lets study the four quadrants

# First quadrant the measure of all angles is between 0 and π/2

the measure of any angle is α

∴ All the angles are acute

∴ All the trigonometry functions of α are positive

# Second quadrant the measure of all angles is between π/2 and π

the measure of any angle is π - α

∴ All the angles are obtuse

∴ The value of sin(π - α) only is positive

sin(π - α) = sin(α) ⇒ csc(π - α) = cscα

cos(π - α) = -cos(α) ⇒ sec(π - α) = -sec(α)

tan(π - α) = -tan(α) ⇒ cot(π - α) = -cot(α)

# Third quadrant the measure of all angles is between π and 3π/2

the measure of any angle is π + α

∴ All the angles are reflex

∴ The value of tan(π + α) only is positive

sin(π + α) = -sin(α) ⇒ csc(π + α) = -cscα

cos(π + α) = -cos(α) ⇒ sec(π + α) = -sec(α)

tan(π + α) = tan(α) ⇒ cot(π + α) = cot(α)

# Fourth quadrant the measure of all angles is between 3π/2 and 2π

the measure of any angle is 2π - α

∴ All the angles are reflex

∴ The value of cos(2π - α) only is positive

sin(2π - α) = -sin(α) ⇒ csc(2π - α) = -cscα

cos(2π - α) = cos(α) ⇒ sec(2π - α) = sec(α)

tan(2π - α) = -tan(α) ⇒ cot(2π - α) = -cot(α)

* Now lets solve the problem

A. The measure of the angle 13π/6 = π/6 + 2π

- The means the terminal of the angle made a complete turn (2π) + π/6

∴ The angle of measure 13π/6 lies in the first quadrant

∴ sec(13π/6) = sec(π/6)

∵ sec(x) = 1/cos(x)

∵ cos(π/6) = √3/2

∴ sec(π/6) = 2/√3 ⇒ multiply up and down by √3

∴ sec(π/6) = 2/√3 × √3/√3 = 2√3/3

* The exact value of sec(13π/6) = 2√3/3

B. The measure of the angle 7π/4 = 2π - π/4

- The means the terminal of the angle lies in the fourth quadrant

∴ The angle of measure 7π/4 lies in the fourth quadrant

- In the fourth quadrant cos only is positive

∴ cot(2π - α) = -cot(α)

∴ cot(7π/4) = -cot(π/4)

∵ cot(x) = 1/tan(x)

∵ tan(π/4) = 1

∴ cot(π/4) = 1

∴ cot(7π/4) = -1

* The exact value of cot(7π/4) = -1

5 0

3 years ago

Can some one help who actually knows the answer!

Naya [18.7K]

Answer:

well explict means stated clearly and in detail, leaving no room for confusion or doubt. and implict means implied though not plainly expressed.

Step-by-step explanation:

6 0

2 years ago

The domain and range of 5x squared plus 10x what is the domain and range of f of x equals 5x squared plus 10x

liberstina [14]

Answer:

Domain: set of all real numbers

Range: $y \geq -5$

Step-by-step explanation:

We have to find the domain and range of the function:

$f(x) =5x^2+10x$

This is a quadratic function, shape of a "U", that's called a parabola.

The domain is the set of x values for which the function is defined.

The range is the set of y values for which the function is defined.

Normally, any parabola in the form $ax^2+bx+c$ has domain as "all real numbers". This is the case for this problem as well, thus,

Domain = set of all real numbers

Now, for the range, we have to look at the minimum value of the function. So, the range would be y values greater than or equal to the minimum number. Lets find the minimum value of this function.

We have to find the value of x for which the minimum occurs by using the formula:

$x=\frac{-b}{2a} =\frac{-10}{2(5)} =-1$

<em><u>Note: value of a is "5" and b is "10"</u></em>

Now, we plug this into the function to find the minimum value:

$f(x)=5x^2+10x\\f(-1)=5(-1)^2 +10(-1)\\f(-1)=-5$

So, the range is set of all real numbers greater than or equal to -5.

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3 years ago

Helloo! I really need help on this!

barxatty [35]

The answer is c. The range fo the length of the fish caught by Freddy is greater than the range of the length of the fish caught by Waldo.

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