Hydrogen reacts with oxygen based on the following equation:
2 H2<span> + O</span>2<span> → 2 H</span>2<span>O
</span>
From the periodic table:
molar mass of hydrogen = 1 gram
molar mass of oxygen = 16 grams
From the balanced equation above, we can find that:
4 grams of hydrogen react with 32 grams of oxygen to produce 36 grams of water.
This means that: 0.73 grams of hydrogen require (0.73x32) / 4 = 5.84 grams of oxygen to react with.
Since only 3.28 grams of oxygen are reacting, this means that oxygen is our limiting reagent and that the reaction would stop once the amount of oxygen is consumed.
So, we will base our calculations on oxygen.
mass of water produced from 3.28 grams of oxygen can be calculated as follows:
mass of water = (3.28 x 36) / 32 = 3.69 grams
Answer:
This question is incomplete
Explanation:
This question is incomplete, however, element R and element Q having the same number of valence electrons means they belong to the same group in the periodic table which is the reason for there similar chemical behavior (as elements in the same group tend to have the same chemical properties).
Element R having fewer energy level (or electron shell) than element Q shows element R has fewer number of electrons than element Q and can be found earlier in the periodic table (or group in particular) when compared to element Q
Answer:
<h2>Transverse wave,</h2>
Explanation:
<h3>motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, seismic S (secondary) waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves.</h3>
This element is beryllium.
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Answer:
Explanation:
(a) Part 1: 
reaction. This is a nucleophilic substitution reaction in which we have two steps. Firstly, chlorine, a good leaving group, leaves the carbon skeleton to form a relatively stable secondary carbocation. This carbocation is then attacked by the hydroxide anion, our nucleophile, to form the final product.
To summarize, this mechanism takes places in two separate steps. The mechanism is attached below.
Part 2: 
reaction. This is a nucleophilic substitution reaction in which we have one step. Our nucleophile, hydroxide, attacks the carbon and then chlorine leaves simultaneously without an intermediate carbocation being formed.
The mechanism is attached as well.
(b) The rate determining step is the slow step. Formation of the carbocation has the greatest activation energy, so this is our rate determining step for . For , we only have one step, so the rate determining step is the attack of the nucleophile and the loss of the leaving group.
