Use the zero product property to find the solutions to the equation 6x2 – 5x = 56.
2 answers:
Consider the given equation
We have to use the zero product property to evaluate the solutions to the given equation.
The Zero product property states that "The product of factors is zero if and only if one or more of the factors is zero".
Since,
We will use "middle the splitting term" method to evaluate its solutions.
Now, by zero product property,
or
So, the solutions are or
.
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This figure is what we would call a composite figure. A composite figure is a shape that is made up of multiple other shapes. when looking at the pond and the border that surrounds it, we can see that this heart shape is made up of two semi circles and a square. To find the area of the border, we will use the area formulas for semi circles and for squares:
Semi Circle Area Formula:
÷ 2
Square Area Formula: length x width
Pi = 3.14
Radius = Half of the diameter, in this case 6
After finding the area of each shape, we can subtract the 2 ft width to find the area of the flower bed border.
Semi Circle Area Formula:
Square Area Formula: length x width
Pi = 3.14
Radius = Half of the diameter, in this case 6
After finding the area of each shape, we can subtract the 2 ft width to find the area of the flower bed border.
Answer:
We have the function:
f(x) = x^3 - 2*x^2
To sketch this, we need to graph some points, and then just draw a line that passes through the points.
The graph of this equation is shown below.
Now we can complete the question.
If the graph is below the x-axis in some interval, the function is negative in that interval
If the graph is above the x-axis in some interval, the function is positive in that interval.
If the graph goes up in a interval, then the function is increasing in that interval
If the graph goes down on an interval, then the function is decreasing in that interval.
Then:
1) f is------ on the intervals (−∞, 0) and (0, 2).
Here we can see that the graph is below the x-axis in those intervals, then here we have:
f is negative on the intervals (−∞, 0) and (0, 2).
2) f is------ on the interval (2,∞)
Here the answer is positive:
f is positive on the interval (2,∞)
3) fi is ------ on the interval (0, 4/3)
In the graph, you can see that the graph goes down in that interval, then the correct answer here is:
f is decreasing on the interval (0, 4/3)
4) f is------ on the intervals (−∞, 0) and (4/3, ∞).
In this case, we can see that the graph goes up in these intervals, then the correct answer here is:
f is increasing on the intervals (−∞, 0) and (4/3, ∞).
