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nadya68 [22]
3 years ago
5

Which value of a would make the expression 5 1/3÷4/a equivalent to a whole number?

Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

Any number that is multiples of 33,6,9,12

Step-by-step explanation:

Have a great day!!

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Find the general solution for differential equation<br><br> (D4 - 5D3 + 5D2 + 5D - 6)y = 0
slava [35]
Given differential equation, (D4 - 5D3 + 5D2 + 5D - 6)y = 0

=> For general solution of equation,

Solve D4 - 5D3 + 5D2 + 5D - 6 = 0

=> D4 - 5D3 + 6D2 - D2 + 5D - 6 = 0

=> D2 (D2 - 5D + 6) - (D2 - 5D + 6) = 0

=> (D2 - 5D + 6)(D2 - 1) = 0           ................................(1)

Now

D2  - 1 = (D - 1)(D + 1)  and

Factors of D2 - 5D + 6

D2 - 5D + 6 = D2 - 2D - 3D + 6

= D(D - 2) - 3(D - 2)

= (D - 3)(D - 2)

Therefore, equation (1) implies

(D2 - 5D + 6)(D2 - 1) = (D - 3)(D - 2)(D - 1)(D + 1) = 0

=> D = 3, 2, 1, -1 or D = -1, 1,, 2, 3

=> General solution of differential equation is,<span>

=><span> y = C1 e-x + C2 ex + C3 e2x + C4 e3x</span> .

Hope it helps
</span>
8 0
3 years ago
The question is in the photo above plz answer
frutty [35]

Answer:

surface area of cuboid=2(lb+bh+hl)

surface area of cuboid=2(12×5+5×2+2×12 )

surface area of cuboid=188in²

5 0
3 years ago
Help please. I cant afford to get this wrong
lutik1710 [3]

Answer:

i think A

Step-by-step explanation:

3 0
3 years ago
If x&gt;7, then |x|&gt;7. |y|&gt;7, so y=7<br><br><br> Valid or invalid?
Alex

\text{if }x>7\text{, then }|x|>7 is a valid argument

|y|>7\text{, so }y=7 is not a valid argument

For the first argument: \text{if }x>7\text{, then }|x|>7

From the definition of absolute value function

|x|=x   if x\ge0

That is every positive number is its own absolute value. Since

x>7\implies x\ge0,

we can argue that

x>7\implies |x|>7

so the first argument is valid

For the second argument: |y|>7\text{, so }y=7

From the definition of absolute value function

|y|:=\left \{ {y\text{  if }y\ge0}\atop{-y\text{  if }y

This means that

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{-y>7\text{  if }y

or

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{y

no part of the definition allow for the option y=7. So the second argument is not valid.

Learn more here: brainly.com/question/11897796

7 0
3 years ago
5-3x =-10 what is x?
Delvig [45]

Answer:

x = 5

Please tell me if im incorrect and hope this helped ^^

3 0
3 years ago
Read 2 more answers
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