The answer to the question
Answer: The molar concentration of acetic acid in the vinegar is 0.539 M.
Explanation:
The formula used is:

where,
and
are the concentration and volume of base.
and
are the concentration and volume of an acid.
Given:
Molar concentration of NaOH = 0.1798 M
Volume of NaOH = 30.01 mL
Volume of acetic acid = 10.0 mL
Now putting all the given values in the above formula, we get:

Thu, the molar concentration of acetic acid in the vinegar is 0.539 M.