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3 years ago

Fluorine has the electron configuration 1s22s22p5. With which of the following elements would fluorine form an ionic bond?

Chemistry

1 answer:

Rashid [163]3 years ago

5 0

Fluorine since it is a halogen (non-metal), then it would need to bond with a metal in order to form an ionic bond.

Fluorine would therefore need an element from any of the metal groups to bond with in order to form an ionic compound e.g. Group One (Sodium or Lithium) or Group Two (Magnesium or Calcium) or Group Three (Aluminum) or a Transitional metal (Copper or Vanadium).

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22.4 L of hydrogen is taken in a cylinder at zero degree Celsius and at one atm. This gas is transferred to a cylinder of 11.2 L

geniusboy [140]

Answer:

2 Atm; 2.016 g

Explanation:

Changing the volume without changing the temperature or mass only changes the pressure. Volume and pressure are inversely proportional so halving the volume will double the pressure.

P = 1 Atm, T = 0 °C are "standard" temperature and pressure (STP). The volume of 1 mole of gas is 22.4 L under these conditions. That means the amount of hydrogen gas in the cylinder is 1 mole, so has a mass of 2.016 g.

After the volume reduction, the pressure is 2 Atm, and the mass remains 2.016 g.

7 0

3 years ago

Read 2 more answers

What happens to an oxidizing agent during a redox reaction?

Gnoma [55]

Answer:

An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. ... A reducing agent is oxidized, because it loses electrons in the redox reaction.

Explanation:

An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. ... A reducing agent is oxidized, because it loses electrons in the redox reaction.

4 0

3 years ago

How did democtitis define atom?

klemol [59]

Democritus, theorized that atoms were specific to the material which they composed. In addition, Democritus believed that the atoms differed in size and shape, were in constant motion in a void, collided with each other; and during these collisions, could rebound or stick together.

<u>Explanation:</u>

One of the main atomic theorists was Democritus, a Greek philosopher who lived in the fifth century BC. Democritus realized that if a stone was partitioned fifty-fifty, the two parts would have indistinguishable properties from the whole.
Therefore, he contemplated that if the stone were to be constantly cut into littler and littler pieces at that point; sooner or later, there would be a piece that would be so little as to be inseparable. He called these small pieces of matter as "atomos", the Greek word for inseparable.

Democritus estimated that atoms were explicit to the material which they made. Also, Democritus accepted that the particles varied in size, were an inconsistent shape, crashed into one another; and during these impacts, could bounce back or stay together. Hence, changes in the matter were a consequence of separations or mixes of the atoms as they moved all through the void.

8 0

3 years ago

Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of

Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

5 0

3 years ago

What is the volume occupied by 4.20 miles of oxygen gas (O2) at STP

Drupady [299]

Answer: 94.13 L

Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP,pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R= 0.08205 L.atm/mol.K.

To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V= 4.20 mol( 0.08205L.atm/mol.K)(273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.

8 0

3 years ago