80 ...........................
Answer:
Check the explanation
Step-by-step explanation:
(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n
(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)
Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1
(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite
Answer:
Expand:
x^2+7x-2x-14
Answer:
x^2+5x-14
Step-by-step explanation:
Answer:
Step-by-step explanation:
10
Answer:
Step-by-step explanation:
A square is a <u>shape that which all sides are equal</u>
<em>14 is one side of the square and to find the area of a square/rectangle, you do </em><u><em>length*width </em></u>
14*14=196
