Answer:
6^3=6×6×6=216. So, the answer is 6x6x6 and 216.
Answer:
A
Step-by-step explanation:
To sovle this we must combine the numbers togther and the variables togther.
We have:
8c+6-3c-2
Lets take out the c's and combine them:
8c -3c
=
5c
Now lets take out the numbers:
6-2
=
4
Now lets put these back together and we get the expression:
5c+4
This looks like A.
Hope this helps! :D
What don't you get about the problem ?
Answer:
b is the answer
Step-by-step explanation:
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
