Answer: 1) D
2) C
Step-by-step explanation:
1. The blue algae has an initial mass of 20 kg and doubles its mass every hour. Then after t hours, the mass of blue algae is
2. The green algae has an initial mass of 160 kg and grows at a constant rate of 0.20 kg per minute. Then after t hours (60t minutes), the mass of green algae is
Part I) At t=3:
The mass of green algae has 196-160=36 kg more mass at 3 hours.
Part II) At t=4:
The blue algae has 320-208=112 kg more mass at 4 hours.
Answer:
Step-by-step explanation:
we are given
we have to find f/g
we can write as
now, we can plug values
and we get
so,
we know that denominator can not be zero
so,
now, we can solve for x
Divide both sides by 5
and we get
A)
s = sweater
j = jeans
Equations:
4s + 2j = 140
2s + 3j = 150
B)
4s + 2j = 140
2s + 3j = 150
Multiply (-2) to the second equation
-2 (2s + 3j = 150)
-4s - 6j = -300
Now you have the equations:
4s + 2j = 140
-4s - 6j = -300
-----------------------------add
-4j = -160
j = 40
4s + 2(40) = 140
4s + 80 = 140
4s = 60
s = 15
The cost for a sweater is $15 and the cost for a jean is $40
We used the elimination method to solve the system of equations.
C)
Each pair of jean, she will buy 3 sweaters so total = 40 + 3(15) = $85
Total cost for 1 pair of jeans and 3 sweaters = $85
If she has $225 the
$225 / $85 = 2.64
2 jeans = 2 x 40 = $80
6 sweaters = 6 x $15 = $90
So She can only buy 2 jeans and 6 sweaters
Answer: 2 × 3 × 3 or we can also write them as 2 × 32, where 2 and 3 both are prime numbers.
Answer:
Both ratios reduce to the same ratio 3/50, so the restocking fee is proportional.
Step-by-step explanation:
For the $200, the restocking fee is $12, so the ratio of the restocking fee to the price of the item is 12/200.
For the $150, the restocking fee is $9, so the ratio of the restocking fee to the price of the item is 9/150.
Now we find out if the ratios 12/200 and 9/150 are equal.
12/200 = 3/50
9/150 = 3/50
Both ratios reduce to the same ratio 3/50, so the restocking fee is proportional.
