Answer:
The simplified expression for the fraction is 
Explanation:
From the given information:
O3* → O3 (1) fluorescence
O + O2 (2) decomposition
O3* + M → O3 + M (3) deactivation
The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)
The rate of decomposition is = k₂ × cO
The rate of deactivation = k₃ × cO × cM
where cM is the concentration of the inert molecule
The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:



since cM is the concentration of the inert molecule
Here's a short answer
Bye Felicia
Answer:
449 (g K) / 39.1 (g/mol K) = 11.5 mol K
Explanation:
Potassium has atomic number 39.1
amount of K in 449g sample = 449/39.1 = 11.5 mol
Well from my research I've calculated that pH + pOH = 14.00. in conclusion
pOH = 14.0 - 4.0 and so forth that equals 10.0 your welcome
Answer:
They are all physical exept c
Explanation: