Answer is: The atomic size of the chlorine ion is larger than the size of the chlorine atom.
Covalent radii of chlorine atom (Cl) is 0.099 nm and ionic radii of chlorine anion (Cl⁻) is 0.181 nm.
Difference between an chlorine atom and chlorine anion is the number of electrons that surround the nucleus.
Chlorine atom has 17 electrons and chlorine anion has 18 electrons.
Answer:
The purpose of molecular modeling is to provide a three-dimensional image (either physical or software-based) that allows a chemist to better see the manner in which atoms and molecules can interact. These models can be used to interpret existing observations or to predict new chemical behavior.
Explanation:
It can describe shape and how they connect while forming the electrons.
Answer: Option (b) is the correct answer.
Explanation:
The elements which have excess or deficiency of electrons will react readily.
Atomic number of Mn is 25 and electronic configuration of 
is [Ar]
. This configuration is stable.
Atomic number of Cr is 24 and electronic configuration of 
is [Ar]
. This configuration is not stable.
Atomic number of Fe is 26 and electronic configuration of 
is [Ar]
. This configuration is stable.
Atomic number of Cu is 29 and electronic configuration of 
is [Ar]
. This configuration is not stable.
Atomic number of Al is 13 and electronic configuration of Al is 
. This configuration is not stable.
Atomic number of Ba is 56 and electronic configuration of 
is [Kr]
. This configuration is stable.
Atomic number of Mg is 12 and electronic configuration of 
is 
. This configuration is stable.
Atomic number of Sn is 50 and electronic configuration of Sn is [Kr]
. This configuration is stable.
Thus, we can conclude that out of the given options, only Fe and reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.
Answer:
2H2S + 3O2 → 2SO2 + 2H2O
V(O2) = 48.4 L
p = 105 kPa = 1.036 atm
T = 190 + 273 = 463 K
Ideal gas law:
pV = nRT
n = \frac{pV}{RT}n=
RT
pV
R = 0.08206 L×atm/mol×K
n(O2) = \frac{1.036 \times 48.4}{0.08206 \times 463}=1.319 \; mol=
0.08206×463
1.036×48.4
=1.319mol
According to the reaction:
n(H2S) = \frac{2}{3}
3
2
n(O2) = \frac{2}{3} \times 1.319 = 0.8798 \;mol
3
2
×1.319=0.8798mol
V = \frac{nRT}{p} \\ V(H_2S) = \frac{0.8798 \times 0.08206 \times 463}{1.036}=32.26 \;LV=
p
nRT
V(H
2
S)=
1.036
0.8798×0.08206×463
=32.26L
Answer: 32.26 L
Explanation:
Answer:
18 moles
Explanation:
Here the combustion of one mole of glucose ----> carbon dioxide + water, releases 2870 kilojoules / moles.
_______________________________________________________
With one contraction cycle requiring 55 kilojoules,
2870 / 55 ≈ 52.18
And with the efficiency being 35 percent,
52.1818..... * 0.35 = ( About ) 18 moles
<u><em>Hope that helps!</em></u>
