The intermolecular forces, such as hydrogen bonds or van der Waals attractions, which draw one molecule to its neighbors, govern a substance's physical properties. Due to the relatively weak intermolecular forces of attraction, molecular substances typically take the form of gases, liquids, or low melting point solids.

<h3>How do the intermolecular forces affect physical properties?</h3>

The forces that bind two molecules together are known as intermolecular forces. Intermolecular forces have an impact on physical properties. Strong and weak forces both exist; the stronger the force, the more energy is needed to separate the molecules from one another. As intermolecular forces increase melting, boiling, and freezing points rise.

The following intermolecular forces are listed in order of strength:

Van der Waals dispersion forces
Van der Waals dipole-dipole interactions
Hydrogen bonding
Ionic bonds

It would take very little energy to separate two molecules if they are connected by van der Waals dispersion forces. On the other hand, it requires a lot more energy to separate two molecules that are joined together by ionic bonds.

To know more about molecules refer to: brainly.com/question/1819972

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8 0

1 year ago

Identify a cation. Group of answer choices an atom that has lost a proton. an atom that has gained an electron an atom that has

pshichka [43]

Answer: An atom that has gained an electron.

Explanation:

The number of protons in an atom cannot change except for some exceptional circumstances.

Cations (or metal ions) are formed when atoms lose electrons, as they want to form a complete outer electron shell to become as stable as possible.

For example, potassium is a 1+ ion, because it has one electron in its outer shell (and in group one). Therefore, to become more stable that electron is lost to become an ion or cation. As one electron is lost, the potassium cation charge is 1+ as the charge of an electron is 1-.

3 0

2 years ago

Write an equilibrium expression for each chemical equation involving one or more solid or liquid reactants or products.

Alex_Xolod [135]

Answer:

$Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}$

$Keq=[O_2]^3$

$Keq=\frac{[H_3O^+][F^-]}{[HF]}$

$Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}$

Explanation:

Hello there!

In this case, for the attached reactions, it turns out possible for us to write the equilibrium expressions by knowing any liquid or solid would be not-included in the equilibrium expression as shown below, with the general form products/reactants:

$Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}$

$Keq=[O_2]^3$

$Keq=\frac{[H_3O^+][F^-]}{[HF]}$

$Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}$

Regards!

5 0

2 years ago