If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.
The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.


The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.
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<em>The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.</em>
Answer:
The difference in temperature is significant means that the lower-boiling liquid finishes distilling at a temperature that is too low for the higher-boiling liquid to be in vapor form yet.
Explanation:
The temperature will rise as the vapor of lower-boiling liquid rushes into the distillation head. However once the lower-boiling liquid is done distilling, there is a temperature drop because while the lower temperature liquid is done distilling, the temperature is still too low for the higher-boiling liquid to be rushing in as a vapour, so the temperature drops.
<span>small organic molecules will not dissolve in water cannot be synthesized by body (except vitamin D) supplements packaged in oily gel caps excesses can cause problems since fat-soluble vitamins are not excreted readily</span>
Pressure varies in the atmosphere because air molecules are being pulled down towards the center of the earth-hope this helps!
Answer:
0.86L.
Explanation:
1mol of Zn has mass of 65.39g . The amount of Zn is 2.5g65.39g/mol=0.038mol