Question

What is the answer for No.22 & 23 please

Answer 1

Hello!

Number 22: We'd plot the first point at 0 since there is no stated y-intercept. Next, we'd use our slope to determine where to plot the next point, and that would create our line. According to the problem, our slope is $-\frac{1}{2}$, which automatically tells us that the slope would be going downwards because it's negative. 

To plot our point, use the slope while going down and across from our y-intercept, which is 0. Go down 1, and over 2.

Your points should be at (0, 0) and (-1, 2)


Number 23: This one will be a bit trickier since the equation is not in slope-intercept form. First, let's convert it to slope-intercept form. 

$-2x + 3y = 6 -2x + 2x + 3y = 6 + 2x 3y = 6 + 2x 3y/3y = 6/3y + 2x/3y y = 2 + 2/3x$

Flip some of those numbers around to get our equation in slope-intercept form:

$y = \frac{2}{3}x + 2$

Now to graph this, we do the same as we did for the last problem. Plot our first point at (0, 2), since 2 is our y-intercept. Afterwards, go up 2 and over 3, then plot the other point.

Your points should be at (0, 2) and (4, 3)