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3 years ago

Which of the following shows the graph of y = 4x + 3?

Mathematics

2 answers:

gladu [14]3 years ago

4 0

It would be the graph with the line at the 3 on the y axis and with points going up 4 and over 1

LiRa [457]3 years ago

4 0

The given equation is y = 4x + 3.

Comparing it with slope-intercept form of line i.e. y = mx + b.

Slope of the line is m = 4.

Y-intercept of the line is b = 3.

This is a straight line graph going upward from left to right direction with rise-over-run as 4 over 1 and passing through (0, 3) on y-axis.

Its graph would look like as follows :-

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Solve for x. X/4+1=3?

Elan Coil [88]

Subtract 1: x/4=2 multiply by 4: x=8 which is the answer

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3 years ago

Review: Angle Bisectors

zmey [24]

Answer:

m∠AOC = 15°

m∠BOC = 15°

Step-by-step explanation:

Given the angle ∠AOB

It is stated that CO is the angle bisector of ∠AOB.

Given that ∠AOB = 30°

As we know that the angle bisector bisects the angle into two equal angles.

Thus, the angle bisector CO bisects the angle ∠AOB into two equal angles, which are:

m∠AOC

m∠BOC

∠AOB = 30°

Thus, the two formed angles i.e m∠AOC and m∠BOC by the angle bisector would be half of the angle bisector as the angle bisector bisects the angle ∠AOB into two equal angles.

Therefore,

m∠AOC = 15°

m∠BOC = 15°

7 0

3 years ago

Ellie earns money by raking leaves. She earns $2.25 for each bag she fills with leaves. This week, she earns $24,75. How many ba

Pepsi [2]

Answer:

she raked 11 bags of leaves

Step-by-step explanation:

24.75 divided by 2.25= 11

8 0

2 years ago

Find an equation of the tangent line to the graph of the function f(x) = 2sinx at the point where x = pi/3.

BigorU [14]

The equation of the tangent line of f(x) is given by y = f'(x)x + c
f(x) = 2sin x
f'(x) = 2cos x

At x = pi/3
f'(pi/3) = 2 cos(pi/3) = 1
f(pi/3) = 2 sin(pi/3) = √3
√3 = 1(π/3) + c
c = √3 - π/3

Therefore, required equation is
y = x + √3 - π/3

3 0

3 years ago

Just a quick question.

Wittaler [7]

$250. Hope this helps :)

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