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3 years ago

What is the recursive rule for this geometric sequence?

Mathematics

2 answers:

9966 [12]3 years ago

4 0

The recursive formula for this is the first option or A.

Molodets [167]3 years ago

4 0

Answer:

Step-by-step explanation:

ok so first of all the question is 3 3/2 3/4 3/8

and the answers are

a1=1/2;an=3*an-1

a1=3/2;an=1/2*an-1

a1=1/2;an=2/3*an-1

a1=3;an;an=1/2*an-1 <== and this is the correct one

hope this helps and were your seat belt

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Help, please!

Agata [3.3K]

B=A the are the same angle B and A

6 0

3 years ago

The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP

Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d } = 30

5(2a + 4d )d = 60

10a + 20d = 60

reduce to lowest term to easy calculation by dividing through by 10

a + 2d = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉ = ⁹/₂(2a + 8d ) = 69

9(2a + 8d ) = 30 + 69

18a + 72d = 99 x 2

18a + 72d = 198

divide through by 18 to reduce to lowest time

a + 4d = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

a + 2d = 6

a + 4d = 11

-2d = -5

d = ⁵/₂.

Now substitute for d to get a

a + 2(⁵/₂) = 6

a + 5 = 6

a = 6 - 5

a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

7 0

3 years ago

In an experiment to measure the lifetimes of parts manufactured from a certain aluminum alloy, 73 parts were loaded cyclically u

kari74 [83]

Answer:

0.0094.

Step-by-step explanation:

For the given experiment, let X be the lifetimes of parts manufactured from a certain aluminum alloy.

sample size =73

Sample mean = 784

Sample standard deviation = 120

Let µ represent the mean number of kilocycles to failure for parts of this type.

Null hypothesis, H0 : µ ≤ 750

Alternative hypothesis, H1 : µ > 750.

$z=\dfrac{\overline{X}-\mu}{\frac{s}{\sqrt{n}}}$

where,

$\overline{X}$ is sample mean.

$\mu$ is population mean.

s is sample standard deviation.

n is the sample size.

$z=\dfrac{783-750}{\frac{120}{\sqrt{73}}}$

$z=2.35$

It is a right tailed test because alternative hypothesis is µ > 750. So, P-value is the probability of observing a sample mean greater that 783 or the probability of P(z>2.35).

$P=P(z>2.35)$

$P=1-P(z$

$P=1-0.9906$

$P=0.0094$

Therefore the P-value is 0.0094.

5 0

3 years ago

Which function is the inverse of f(x)=4x-1?

Nitella [24]

The function x+1 all over 4 equals y. x+1 is in the numerator and 4 is in the denominator of the fraction that equals y.

7 0

3 years ago

Simplify the ratio 4 22 30

GenaCL600 [577]

The answer is 2:11:15
you simply divide the number by 2

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4 years ago