Question

With steps... Thanks..

Answer 1

Answer:

$\boxed{-25x-y}$

$\boxed{-p^2q +5pq^2}$

Step-by-step explanation:

$(-15x+6y)-(10x+7y)$

Distribute negative sign.

$-15x+6y-10x-7x$

Combine like terms.

$\boxed{-25x-y}$

$2pq(p+q)- (3pq(p-q))$

Expand brackets.

$2p^2 q+2pq^2 -(3p^2q-3pq^2)$

Distribute negative sign.

$-3p^2q+3pq^2+2p^2q+2pq^2$

Combine like terms.

$\boxed{-p^2q +5pq^2}$

Answer 2

Answer:

a. -25x - y

b. pq ( - p + 5q )

Step-by-step explanation:

a.

$- 15x + 6y - (10x + 7y)$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

$- 15x + 6y - 10x - 7y$

Collect like terms

$- 15x - 10x + 6y - 7y$

$- 25x - y$

b.

$2pq(p + q) - 3pq(p - q)$

Factor out pq from the expression

$pq(2(p + q) - 3(p - q))$

Distribute 2 through the parentheses

$pq \: (2p + 2q - 3(p - q)$

Distribute -3 through the parentheses

$pq \: (2p + 2q - 3p + 3q)$

Collect like terms

$pq( - p + 5q)$

Hope this helps...

Best regards!!