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Fofino [41]
3 years ago
15

Pls solve! Show work! If you give an explanation or show work I will mark brainliest!

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
8 0
Y = 9x
y = 5x + 24

9x = 5x + 24
9x - 5x = 24
4x = 24
x = 24/4
x = 6

y = 9x
y = 9(6)
y = 54

solution (6,54)....x = 6 and y = 54
Korolek [52]3 years ago
5 0
You can solve this using substitution.
y= 9x
y=5x+24
Start by setting the two equations equal to one another. 
9x = 5x+24
Put all the x's on one side.
4x=24
x=6
Now, plug the x-coordinate into any of the systems to find the y-coordinate.
y=9x
y=9(6) = 54

x=6, y=54

Hope this helps :)
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In a class there are 25 students 15 are boys what percentage are girls​
tankabanditka [31]

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40%

Step-by-step explanation:

Total students = 25

Boys = 15

Girls = 25 - 15 = 10

Percent of girls = 10/25

Percent is out of 100.

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=> Cross multiply

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7 0
3 years ago
Solve 2x2 + x − 4 = 0. x2 + x + = 0
Ksenya-84 [330]

Answer:

The Quadratic Polynomial is

2 x² +x -4=0

Using the Determinant method to find the roots of this equation

x=\frac{-1\pm \sqrt{1^2-4*2*(-4)}}{2\times 2}\\\\ x=\frac{-1 \pm \sqrt{32}}{4}{\text{Using the formula}}x=\frac{-b\pm\sqrt{D}}{2a}, {\text{where}},D=b^2-4 ac

For, the Quadratic equation , ax²+ b x+c=0

(b) x²+x=0

x × (x+1)=0

x=0  ∧ x+1=0

x=0     ∧   x= -1

You can look the problem in other way

the two Quadratic polynomials are

2 x²+x-4=0, ∧ x²+x=0

x²= -x

So, 2 x²+x-4=0,

→ -2 x+x-4=0

→ -x -4=0

→x= -4

∨

x² +x² +x-4=0

x²+0-4=0→→x²+x=0

→x²=4

x=√4

x=2 ∧ x=-2

As, you will put these values into the equation, you will find that these values does not satisfy both the equations.

So, there is no solution.

You can solve these two equation graphically also.

3 0
4 years ago
Read 2 more answers
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