In a class there are 25 students 15 are boys what percentage are girls
1 answer:
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Answer:
x = 67.50 ft
Step-by-step explanation:
Consider, ΔMAB and ΔMNP,
∠M = ∠M (Common)
Given AB║NP and let MN as transversal,
∠MAB = ∠MNP (alternate angle)
Also, Given AB║NP and let MP as transversal,
∠MBA = ∠MPN (alternate angle)
Therefore, ΔMAB ≅ ΔMNP (By AAA similarity )
Thus, by CPCT,
consider first two ratios,
Substitute the values, MA = MN - AN = 49.5 ft
On solving for x , we get, x = 67.50 ft
Thus, value of x is 67.50 ft
Answer:
P(X>4)= 0.624
Step-by-step explanation:
Given that
n = 10
p= 0.5 ,q= 1 - p = 0.5
Two fifth of 10 = 2/5 x 10 =4
It means that we have to find probability P(X>4).
P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)
We know that
P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)
P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205
P(X>4)= 0.624